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4 years ago

-7 2/3 +(-5 I/2) + 8 3/4=

Mathematics

1 answer:

Monica [59]4 years ago

4 0

Answer:-53/12

Step-by-step explanation:

-7 2/3+(-5 1/2)+8 3/4

-7 2/3-5 1/2+8 3/4

-23/3 - 11/2 + 35/4

(4x-23 - 6x11 + 3x35)/12

(-92-66+105)/12=-53/12

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What is the mean absolute deviation for the data set? {10, 15, 18, 20, 24}

Arlecino [84]

Answer:

3.92

To find the mean absolute deviation of the data, start by finding the mean of the data set.

Find the sum of the data values, and divide the sum by the number of data values.

Find the absolute value of the difference between each data value and the mean: |data value – mean|.

Find the sum of the absolute values of the differences.

Divide the sum of the absolute values of the differences by the number of data values.

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3 years ago

Read 2 more answers

What would I put to show my work?

fredd [130]

Answer:

x = 23

Step-by-step explanation:

These are supplementary angles so the sum of those angles add up to 180:

3x + 16 + 5x - 20 = 180

8x - 4 = 180

8x = 180 + 4

8x = 184

x = 184/8

x = 23

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3 years ago

Which of the following is the correct factored form of the given equation? 6x^2 -13x - 8 = 0

tester [92]

Answer:

the 2nd

Step-by-step explanation:

8 0

3 years ago

he Nassau Bahamas Community College (NBC) claims that students who take statistics spend on average 19 hours a week working. The

Virty [35]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

At the null hypothesis, it is tested if they spend on average 19 hours a week working, that is:

$H_0: \mu = 19$

At the alternative hypothesis, it is tested if they spend more than 19 hours a week working, that is:

$H_1: \mu > 19$

We have the standard deviation for the sample, hence, the t-distribution is used.

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Searching the problem on the internet, it is found that the values of the parameters are:

$\overline{x} = 24.2, \mu = 19, s = 12.59, n = 25$

Hence, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.2 - 19}{\frac{12.59}{\sqrt{25}}}$

$t = 2.07$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 25 - 1 = 24 df is of $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

3 0

3 years ago

What is the answer to x/6-5=(-13)?

Sophie [7]

Step 1: Simplify both sides of the equation.x6−5=−13Simplify: (Show steps)16x−5=−13Step 2: Add 5 to both sides.16x−5+5=−13+516x=−8Step 3: Multiply both sides by 6.6*(16x)=(6)*(−8)x=−48

7 0

3 years ago