Integer (+6) - (-2) =

2 answers:

8 0

Try the KISS method. Keep it. Switch. Switch. keep the first number, switch the symbol, then switch the sign of the second number. so it would be 6+2=8

RUDIKE [14]3 years ago

4 0

The answer to your question is 8

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Solve the equation.

mylen [45]

-9/15y+3/21=5/15y-14/21

Move 5/15y to the other side. Sign changes from +5/15y to -5/15y

-9/15y-5/15y+3/21=5/15y-5/15y-14/21

-14/15y+3/21=-14/21

Move 3/21 to the other side. Sign changes from +3/21 to -3/21.

-14/15y+3/21-3/21=-14/21-3/21

-14/15y=-14/21-3/21

-14/21-3/21=-17/21

-14/15y=-17/21

Multiply both sides by -15/14

-14/15y(-15/14)

Cross out 15 and 15, divide by 15 then becomes 1

Cross out 14 and 14, divide by 14 then becomes 1

1*1*y=y

-17/21*-15/14

Cross out 15 and 21 , divide by 3. 15/3=2, 21/3=7

17/7*5/14=85/98

Answer: c. y=85/98

7 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of