(x^3-2x^2-5x+6)÷(x-1) solve using long division, must show work

Find the length of the diameter of a sphere with a surface area of 50.27 ft^2.

Liula [17]

Sphere Surface Area = 4 • π • r²

50.27 = 4 * PI * r^2

50.27 / (4 * PI) = r^2

 4.0003594946 = r^2

r = sq root ( 4.0003594946)

radius = 2.0000898716 

So the diameter = 4.0001797433 

or it is roughly 4 feet

6 0

3 years ago

Omar has 2 3/4 cups of dough to make Dumplings. If he uses 3/16 cup of dough for each dumpling,how many whole dumplings can Omar

Brrunno [24]

Omar can make 14 whole dumplings. You change 2 3/4 cups to an improper fraction ( multiply the denominator and add the numerator ) and you get 11/4. Since you need 3/16 cups for one dumpling you have to find the greatest common denominator which is 16. You multiply 4 by 11 to get the numerator and end up with 44/16. Since you need 3/16 for one whole dumping you divide 44 by 3 and get 14.6 repeating. You cannot have a fraction of a dumpling so you round down and get the answer 14.

5 0

3 years ago

What is the rate of change and initial value for the linear relation that includes the points shown in the table?

uysha [10]

X 1 2 3
y 10 8 6
So find the slope m: (6-10)/(3-1) = -4/2 = -2
Going backwards when x = 0, y will be 12 (you can see this)
So
Initial value: 12, rate of change: −2

4 0

3 years ago

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

a)

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

b)

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

c)

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

What is the quotient 2 1/5 over negative 1/10

valina [46]

Answer:

25

Step-by-step explanation:

4 0

3 years ago

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(x^3-2x^2-5x+6)÷(x-1) solve using long division, must show work​

(x^3-2x^2-5x+6)÷(x-1) solve using long division, must show work