<h3>
Answer:</h3>
3x-5y=7
<h3>
Step-by-step explanation:</h3>
One way to write the equation of a line through two points is ...
... ∆y(x -x1) -∆x(y -y1) = 0
Here, ∆y = 1 -(-5) = 6, and ∆x = 4 -(-6) = 10. These two numbers have a common factor of 2 that can be removed, so we can use the values ...
... ∆y = 3, ∆x = 5 and fill in our equation as ...
... 3(x +6) -5(y +5) = 0 . . . using (-6, -5) for (x1, y1)
... 3x -5y -7 = 0 . . . . . . . . simplify; general form equation
... 3x -5y = 7 . . . . . . . . . . standard form equation
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<em>Comment on 2-point form</em>
Perhaps you more usually see the 2-point form of the equation of a line written as ...
... y -y1 = (y2 -y1)/(x2 -x1)·(x -x1)
If you call y2-y1 = ∆y and x2-x1 = ∆x, then you can multiply by ∆x to get
... ∆x(y -y1) = ∆y(x -x1) . . . . . this might be an easy form to remember
Subtracting the left side gives the form we used above:
... ∆y(x -x1) -∆x(y -y1) = 0
