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3 years ago

Which of the following can cause a communicable disease

Mathematics

1 answer:

velikii [3]3 years ago

8 0

What does "the following" mean ?

Where are the choices ?

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Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

statuscvo [17]

Answer:x=15/52

Step-by-step explanation:

Divided both side by 52

52x/52=15/52

Therefore x=15/52

7 0

3 years ago

Please help this is Properties of Operations

SSSSS [86.1K]

There’s nothing...repost it and I’ll help.

5 0

3 years ago

What would be the first step you would take in simplifying 6 - 3+ 5 x 2 ?

Darya [45]

The first step you would take would be multiplying 5x2

4 0

3 years ago

Read 2 more answers

The value of U.S exports to China increased from $1480 million in 2011 to $2768 million

aliya0001 [1]

The percentage of increase was 87.027... %

Explanation

The value of U.S exports to China increased from $1480 million to $2768 million.

Suppose, the percentage of increase is $x\%$

So, the amount of increase = $x\%$ of 1480 $=1480*\frac{x}{100}=14.8x$

Thus, the equation will be......

$14.8x= 2768-1480\\ \\ 14.8x=1288\\ \\ x= \frac{1288}{14.8}=87.027....$

So, the percentage of increase was 87.027... %

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago