Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Answer:
Y = 12
Step-by-step explanation:
x + 1/3y = 4
Multiply both sides of the equation by 3.
3 ⋅ 1
3 ⋅ y = 3 ⋅ 4
Simplify both sides of the equation:
1. Simplify both sides of the equation.
2. Multiply 3 by 4
How to simplify:
Cancel the common factor of 3
Rewrite the expression.
Multiply by 1
y = 3 ⋅ 4
Multiply 3 by 4
(12)
∠KMN = (1/2)*arc KN . . . . . . this relationship is true of any inscribed angle. (It is a useful relationship to remember.)
= 95°/2
= 47.5°
21.5, just took the test!!!!