15 pointsssssssssssss

If a card s drawn from a normal deck of cards, what is the probability that the card will be an ace?

PtichkaEL [24]

1/13. there's 52 cards in a deck and 4 of each card .so 52÷4=13 .1/13

4 0

4 years ago

If a2 + b2 = 11 how much is b2

dolphi86 [110]

the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality

5 0

4 years ago

Read 2 more answers

Is 1/10 rational or irrational

dlinn [17]

Answer should be rational

7 0

3 years ago

Read 2 more answers

Simplify the expression (3 1/4)^2 to demonstrate the power of a power property. Show any intermittent steps that demonstrate how

vichka [17]

Answer:

By property of power of a power:

$(3^{\frac{1}{4}} )^{2}$ = $3^{(\frac{1}{2})}$

Step-by-step explanation:

Given that $(3^{\frac{1}{4}} )^{2}$

The property of power of a power is given by,

= $(a^{b} )^{2}$

= $(a^{b} )\times (a^{b} )$

= $(a^{(b+b)} )$

Using the property of power of a power:

= $(3^{\frac{1}{4}} )^{2}$

= $(3^{\frac{1}{4}} )\times (3^{\frac{1}{4}} )$

= $3^{(\frac{1}{4}+\frac{1}{4})}$

= $3^{(\frac{1}{2})}$

3 0

3 years ago

If cos(xy) = 3x+1 , find dy/dx

lisabon 2012 [21]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2867070

_______________

dy
Find —— for an implicit function:
dx

cos(xy) = 3x + 1.

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}\big[cos(xy)\big]=\dfrac{d}{dx}(3x+1)}\\\\\\
\mathsf{-\,sin(xy)\cdot \dfrac{d}{dx}(xy)=\dfrac{d}{dx}(3x)+\dfrac{d}{dx}(1)}$

Apply the product rule to differentiate that term at the left-hand side:

$\mathsf{-\,sin(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=3+0}\\\\\\
\mathsf{-\,sin(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=3}\\\\\\
\mathsf{-\,sin(xy)\cdot \left[y+x\cdot \dfrac{dy}{dx}\right]=3}$

Now, multiply out the terms to get rid of the brackets at the left-hand
dy
side, and then isolate —— :
dx

$\mathsf{-\,sin(xy)\cdot y-sin(xy)\cdot x\cdot \dfrac{dy}{dx}=3}\\\\\\
\mathsf{-\,y\,sin(xy)-x\,sin(xy)\cdot \dfrac{dy}{dx}=3}\\\\\\
\mathsf{-\;x\,sin(xy)\cdot \dfrac{dy}{dx}=3+y\,sin(xy)}\\\\\\\\
\therefore~~\mathsf{\dfrac{dy}{dx}=\dfrac{3+y\,sin(xy)}{-\;x\,sin(xy)}\qquad\quad for~~x\,sin(xy)\ne 0\qquad\quad\checkmark}$

and there it is.

I hope this helps. =)

Tags: <span><em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>
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4 0

4 years ago