The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.
5y + 3x = 15 5(0) + 3x = 15 3x + 15 x = 5
We found the x-intercept now find the y-intercept with the same process.
The y-intercept will be at the point (0, y) where y is any real number.
5y + 3x = 15 5y + 3(0) = 15 5y = 15 y = 3
So, the x-intercept is (5, 0) and the y-intercept is (0, 3)
