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3 years ago

Find the x and y intercepts 5y + 3x = 15

1 answer:

8 0

First, find the x-intercept.

The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.

5y + 3x = 15
5(0) + 3x = 15
3x + 15
x = 5

We found the x-intercept now find the y-intercept with the same process.

The y-intercept will be at the point (0, y) where y is any real number.

5y + 3x = 15
5y + 3(0) = 15
5y = 15
y = 3

So, the x-intercept is (5, 0) and the y-intercept is (0, 3)

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Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

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Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

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$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

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15y - 6y = 15x

9y = 15x

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We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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Answer:

Step-by-step explanation:

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No 33% is not unusual.

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