$~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 16 -6}{2}~~~ ,~~~ \cfrac{ 5 -9}{2} \right)\implies \left( \cfrac{10}{2}~~,~~\cfrac{-4}{2} \right)\implies (5~~,~-2)$

7 0

2 years ago

A student of the author earned grades of 92, 83, 77, 84, and 82 on herfive regular tests. She earned grades of 88 on the final e

goblinko [34]

The class is weighted as follows:

60% Regular Tests

10% Final Exam

15% Project

15% Homework

The total weighted points possible for the class are as follows:

(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340

To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:

(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4

So her weighted grade percent would be 285.4/340 = 83.9% which is a B.

8 0

3 years ago

Please answer below :-)

mestny [16]

Answer:

A: 18

Step-by-step explanation:

Hopefully this helps!

3 0

2 years ago