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3 years ago

PLEASE HELP ME I don’t get it

Mathematics

1 answer:

Temka [501]3 years ago

4 0

Split the figure into 3 shapes: a trapezoid,a rectangle and a triangle

Area of trapezoid

A= 1/2(b1+b2) h

A = 1/2(3 +9)(8)

A = 1/2(12)(8)

A = 48 square units

Area of rectangle:

A = L x W

A = 9 x 8

A = 72 square units

Area of triangle

A = 1/2bh

A = 1/2(3)(8)

A = 12 square units

Area of figure = 48 square units + 72 square units + 12 square units

= 132 square units

Answer

132 square units

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Rectangle Given:1=15 m, w=6m,A=

sashaice [31]

Answer:

$90m^2 and 144 m^2$

Step-by-step explanation:

Given :

Length of the rectangle (l)=15m

Width of the rectangle (w)= 6 m

Area of the rectangle can be calculated as :

$A=l*w\\A=(15)(6)\\A=90 m^2$

Now,

Side of square (s)=12 m

Area of the square can be find:

$A=s^2\\A=12^2\\A=144 m^2$

6 0

3 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

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3 years ago

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