Answer:
2 students in each group
Step-by-step explanation:
If there were 5 groups and after a while 7 students leave early and 3 students remain to do the activity, if you add 7 + 3 = 10 divide it by 5, the number of groups in the activity, you would get 2 students in each group.
Answer:
just split the awnser
Step-by-step explanation:
Answer:
she was wrong
Step-by-step explanation:
x-4-11 = 0 (4+-1=4-1)
x=15
hence she was wrong
Answer:
Sum is - 5n² -8n + 4.
Step-by-step explanation:
Given : (3n² – 5n + 6) + (–8n²– 3n – 2) .
To find : Sum .
Solution : We have (3n² – 5n + 6) + (–8n²– 3n – 2) .
Combine like terms :
(3n² - 8n²– 5n - 3n + 6 - 2).
- 5n² -8n + 4.
Therefore, Sum is - 5n² -8n + 4.
R = 25 cm = 0.25 m
α = 2.00 rad /s²
T(heta) = 4 π
ω = T(heta)/ t
ω = α t
α t = 4 π / t
t ² = 2 π
t = √ ( 2π ) = 2.5 s
ω = α t = 2 · 2.5 = 5 rad/s
v = ω r = 5 · 0.25 = 1.25 m/s
(1) a (rad) = ω² r = 25 · 0.25 = 6.25 m/s²
(2) a (rad) = v² / r = ( 1.25 )² / 0.25 = 0.15625 / 0.25 = 6.25 m/s²
