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aleksandrvk [35]
3 years ago
8

write the standard form of the equation of the parabola that has the indicated vertex and whose graph passes through the given p

oint. show all work. vertex(4,7)Point(3,6)
Mathematics
1 answer:
Elanso [62]3 years ago
7 0
Vertex form of parabola is

y = a(x - b)^2 + c   where a is a constant and  the vertex is at the point (b,c)

so here we have

y = a(x - 4)^2 + 7

To find value of a we plug in the point  (3,6)

6 = a(3 - 4)^2 + 7
6 = a + 7
a =  6-7 = -1

so equation is y = -(x - 4)^2 + 7

Covert to standard form:-
y = -(x^2 - 8x + 16) + 7
y = -x^2 + 8x - 9


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Easy question i will mark braineliest
Yuki888 [10]

Answer:

<h2>0.67</h2>

Step-by-step explanation:

5(y - 3.8) = 4.7(y - 4)

Distribute 5 through the parentheses

5y - 19 = 4.7(y - 4)

Distribute 4.7 through the parentheses

5y - 19 = 4.7y - 18.8

Move ' 4.7 y ' to L.H.S and change it's sign

5y - 4.7y - 19 =  - 18.8

Move constant to R.H.S and change it's sign

5y - 4.7y =  - 18.8 + 19

Collect like terms

0.3y =  - 18.8 + 19

Calculate

0.3y = 0.2

Divide both sides of the equation by 0.3

\frac{0.3y}{0.3}  =  \frac{0.2}{0.3}

Calculate

y = 0.67

Hope this helps...

Best regards!!

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The sum of three numbers is 185
Mariana [72]

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The Second Number is 90.

Step-by-step explanation:

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Pls check the attachment :) <br><br>f(x)=x^5-9x^3<br><br>​
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As x —> positive infinity, f(x) —> positive infinity.

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y =  {x}^{5}  - 9 {x}^{3}

An odd-degree function, meaning that the graph starts from negative infinity at x —> negative infinity and positive infinity at x —> positive infinity.

As x —> negative infinity, f(x) —> negative infinity

As x —> positive infinity, f(x) —> positive infinity.

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