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3 years ago

Please help 10 points

Mathematics

2 answers:

svlad2 [7]3 years ago

8 0

I believe the answer is 2

anygoal [31]3 years ago

5 0

I like the other person believe the answer is 2

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When writing 3.7272727272... as a ratio of integers, what is the common ratio?

Law Incorporation [45]

The answer is: "41 / 11 " ; or, write as: " 41 : 11 " .
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Explanation:
__________________________________________________________
72/99 = (72÷9) / (99÷9) = 8/ 11 .

So, 3.727272727272... = "3 $\frac{8}{11}$ " .

→ "3 $\frac{8}{11}$ " = [(11 *3) + 8] / 11 = (33 + 8) / 11 = 41 / 11 .
__________________________________________________________
"41 / 11" cannot be simplified any further; so the answer is:
__________________________________________________________
"41 / 11 " ; or, write as: " 41 : 11 " .
__________________________________________________________

5 0

3 years ago

The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}

CaHeK987 [17]

Answer:

The answer is "domain and range are different".

Step-by-step explanation:

Given:

$f(x) = \sqrt{\frac{x+1}{x-1}}\\\\g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\$

Solve f(x) to find domain and range:

for element x: R:

⇒ $x \leq -1 \ \ \ and \ \ \ x > 1$ range:

$for \ \ f(x) \times element : 0 \leq f(x)< 1 \ \ \ or \ \ f(x)>1$

$g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\$

Solve for domain:

⇒ $\ when \ x \ element \ R: \ \ \ x>1$

Solve for range:

⇒ $g(x) \times element$ R : $g(x)>1$

So, the value of the method f(x) and g(x) (range and domain) were different.

5 0

4 years ago

the pendulum on a grandfather clock swings from side to side once every second. If the length of the pendulum is 3 feet and the

bogdanovich [222]

Check the picture below

thus $\bf s=\cfrac{r\theta\pi }{180}\qquad 
\begin{cases}
s=\textit{arc's length}\\
r=radius\\
\theta=\textit{angle in degrees}\\
----------\\
r=3\\
\theta=10
\end{cases}\implies s=\cfrac{3\cdot 10\cdot \pi }{180}$

3 0

3 years ago

Sadie is 3 years older than Kareem, and Kareem is twice as old as Nadra. The sum of their ages is 33.

Dima020 [189]

Answer:

Step 1-Write an equation, letting x represent Kareem’s age:

(x + 3) + x + 2 x = 33

Step 2-Solve the equation:

(x + 3) + x + 2 x = 33. 3 + 4 x = 33. 4 x = 30. x = 7 1/2.

Step 3-Sadie is 10 1/2, Kareem is 7 1/2, and Nadra is 3 3/4.

Which corrects the student’s first error?

1. In Step 1, the student should have used One-half x to represent Nadra’s age, and written the equation (x + 3) + x +1/2x = 33.

2. In Step 2, the student should have added 3 on both sides of the equation to find a solution of x = 9.

3. In Step 3, the solution represents Sadie’s age. Therefore, Sadie is 7 1/2, Kareem is 4 1/2, and Nadra is 2 1/4.

4. In Step 3, Nadra’s age is the difference between 33 and Sadie’s and Kareem’s ages, so Nadra is 15.

5 0

2 years ago

Select the answer choice that correctly describes the graph (on a number line) of the inequality: h > 7

Lerok [7]

Close circle at 7 with an arrow pointing

right.

hope it helps

6 0

3 years ago