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liberstina [14]

3 years ago

14

The Middle School Are Having A Car Wash To Raise $466.75 For A New Sound System. In The Past,They Washed An Average Of 125 Cars

At Each Car Wash. What Should They Charge Per Car So They Can Reach Their Goal.

1 answer:

masya89 [10]3 years ago

7 0

Answer: $3.74

Step-by-step explanation: $466.75/ 125 = 3.734= $3.74

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Need help with this question plz!!

mel-nik [20]

Let us consider the image on the left that is the image in which 1 and 2 , 3 and 4 are connected as image 1 and the other as image 2.

1. All Vertices are connected by the least amount of edges. True

2. Vertex 1 and 2 are not connected. This is false for image

1 and true for image 2

3. Vertex 3 and 4 are not connected. This is false for image

1 and true for image 2

4. You can get to Vertex 1 from Vertex 4 by going through Vertex 3. This is true for image 1

5 0

3 years ago

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What if i had 2 ducks and add 4 more

Travka [436]

Answer:

You would have 6 ducks

Step-by-step explanation:

8 0

3 years ago

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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

45/4 = 12/2f. what is f?

nata0808 [166]

Answer:

Exact Form:

f=8/15

Decimal Form:

f=1.875

Step-by-step explanation:

45×2f = 4×12

90f = 48

48/90 = 24/45 = 8/15

6 0

3 years ago

Help pls i really need help !!!

bixtya [17]

Answer:

that a tough one i'm guessing its longitude and latitude why not tell your teacher!

5 0

3 years ago