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Marta_Voda [28]
3 years ago
9

Solve for m

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

m = 29/48

Step-by-step explanation:

Given that

x₂ = (y₂-y₁) +10 →(1

y₂ = y₁-x₁ → (2

y₁= 37

x₁ = 29

Now substitute the value of x₁ and y₁ into equation 2

y₂ = 37-29

y₂ = 8

Now substitute the value of y₂ and y₁ into equation 1

x₂ = (8-37) +10

x₂ = -19

As we know the slope (m) can be calculated as follows

m =(y₂ - y₁)/(x₂ - x₁)

m = (8- 37)/(-19 - 29)

m = (-29)/(-48)

m = 29/48

So our slope is 29/48



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McGill types 270 words in six minutes his paper is 630 words if he keeps waving at the same rate and how many more minutes when
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Answer:

8 more minutes.

I think the perfect version in your question is:

<em>McGill types 270 words in six minutes his paper is 630 words if he keeps waving at the same rate and how many more minutes when McGill finish typing his paper</em>

Given that:

  • 270 words in six minutes <=> 1 minute = \frac{270}{6} = 45 words
  • His paper is 630 words

So, the total minutes he needs to finish the paper if  he keeps waving at the same rate is:

\frac{The number of words}{Number of words written in one minute}

= \frac{630}{45}

= 14 minutes.

So he needs 14 minutes to finish writing the paper, but he wrote 270 words in 6 minutes already, so it will take him 14-6 = 8 more minutes.

Hope it will find you well!

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A car assembly line can produce 3 cars per hour. How long would it take to produce 150 cars?
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A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time h
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Answer:

The 95% confidence interval for the difference between the Route B and Route A commuting times is -3.771808 to 1.771808

Step-by-step explanation:

Here we have the confidence interval is given by the following equation;

\left (\bar{x}_1-\bar{x}_{2}  \right ) - z_{c}\sqrt{\frac{\sigma _{1}^{2}}{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + z_{c}\sqrt{\frac{\sigma _{1}^{2}}{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}

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Plugging in the values Solving we get

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