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Snowcat [4.5K]
3 years ago
5

When x = 8, y = 14. Find y when x = 24.

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0

Answer:

Also read the problem carefully to determine if there are any other changes in the inverse ... Example 1 – If x varies inverse as y, and x = 7 when y = 3, find y when x = 9. ... If the volume is 32 cubic centimeters at a pressure of 8 pounds, find the ...

Step-by-step explanation:

liq [111]3 years ago
4 0

y = 42 is the correct answer

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If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
What is the area of parallelogram ABCD?
Gnom [1K]

Answer:

What are the units? 13 x 14 ??or 15 x 16 ?

Step-by-step explanation:

Eitther 182 or 240

5 0
3 years ago
Please help .......You are guaranteed a minimum salary of $2000 per month PLUS 5.75% 5 points
RUDIKE [14]

Answer:

6600

Step-by-step explanation:

0.0575*80000=4600

4600+minimum salary which is 2000=6600

(can I get brainliest please)

5 0
3 years ago
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7 0
3 years ago
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PLEASE HELP WILL MARK BRAINLIEST<br><br>Find the area of the right triangle.
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

This right triangle is on a grid.

The area is the height * base/2

The base is on a line segment parallel to the x axis which is 6 squares.

The height is on a line segment parallel to the y axis which is 2 squares

The area is the height * base /2

Area = 6 * 2 /2 = 12/2 = 6 square units.

4 0
3 years ago
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