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Alla [95]
3 years ago
8

The sketch shows two parallel lines cut by a transversal. Which set of angle pairs are NOT corresponding angles?

Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0
They both aren't. because no right angles.
Mashutka [201]3 years ago
7 0

for TTM its angle 1 and 7


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I have to turn this in, in 8 minutes please help​
FrozenT [24]

Answer:

20h+e

Step-by-step explanation:

e=$220

7 0
3 years ago
Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4
crimeas [40]

We have been given an expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}. We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, a^m\cdot a^n=a^{m+n}, we cab rewrite our given expression as:

\left( 4^{-2+(-3)} \right)^{3}

\left( 4^{-5} \right)^{3}

Now we will use exponent property (a^m)^n=a^{m\cdot n}to further simplify our expression.

\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}

\left( 4^{-5} \right)^{3}= 4^{-15}

Therefore, Chris made mistake in step 2.

8 0
4 years ago
Can someone plz help me on this thank you and please stop giving me links
Brilliant_brown [7]

Answer: 900π

Step-by-step explanation: To calculate the area of a circle, we do πr^2, where r is the radius. The radius is 30, so the answer is 900π.

Hope this helps!

4 0
3 years ago
Denise rolled a number cube several times. The results are shown.
strojnjashka [21]
4/156 so
2/78 so
1/39 so approx. 2.5641%
5 0
3 years ago
Read 2 more answers
Can someone help me plz .. Use these lengths to find cos B, tan B, and sin B.
lara [203]

Answer:

cos B = \frac{7}{25}

tan B = \frac{24}{7}

sin B = \frac{24}{25}

Step-by-step explanation:

In the right triangle, there are three sides and 2 acute angles

  • Hypotenuse ⇒ the opposite side of the right angle
  • Leg1 and Leg 2 ⇒ the sides of the right angle

The trigonometry functions of one of the acute angles Ф are

  • sin Ф = opposite leg/hypotenuse
  • cos Ф = adjacent leg/hypotenuse
  • tan Ф = opposite leg/adjacent leg

In Δ ACB

∵ ∠C is the right angle

∴ AB is the hypotenuse

∵ AC is the opposite side of ∠B ⇒ leg1

∵ CB is the adjacent side of ∠B ⇒ leg2

→ By using the ratios above

∴ cos B = \frac{CB}{AB} , tan B = \frac{AC}{CB} , sin B = \frac{AC}{AB}

∵ CB = 7, AB = 25, AC = 24

∴ cos B = \frac{7}{25}

∴ tan B = \frac{24}{7}

∴ sin B = \frac{24}{25}

6 0
3 years ago
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