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3 years ago

Please Help Find the indicated side of the right triangle

Mathematics

2 answers:

andrew11 [14]3 years ago

7 0

Answer:

3 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan 60 = x/3

3 tan 60 = x

3 sqrt(3) = x

vladimir2022 [97]3 years ago

4 0

Answer:

x = 3 $\sqrt{3}$

Step-by-step explanation:

Using the tangent ratio in the right triangle and the exact value

tan30° = $\frac{1}{\sqrt{3} }$ , then

tan30° = $\frac{opposite}{adjacent}$ = $\frac{3}{x}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

x = 3 $\sqrt{3}$

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*<br> Express the ratio 62:4 in the form n:1

dolphi86 [110]

15.5:1
62/4 = 15.5
15.5 : 1

6 0

3 years ago

Read 2 more answers

I got 13.7 is that correct

Ghella [55]

Answer:

The answer to your question is 10.5 in

Step-by-step explanation:

Data

First triangle

height = x

base = 7 in

Second triangle

height = 12 in

base = 8 in

Process

1.- Use proportions to solve this problem, relates the sides of a triangle with the same sides of the other triangle.

$\frac{x}{7} = \frac{12}{8}$

2.- Multiply both sides by 7

$7\frac{x}{7} = \frac{7(12)}{8}$

3.- Simplify

x = $\frac{84}{8}$

4.- Result

x = 10.5 in

3 0

3 years ago

15 pts + brainliest to right/best answer

den301095 [7]

Split the second term in 5x^2 + 23x + 26 into two terms

5x^2 + 13x + 10x + 26

Factor out common terms in the first two terms, then in the last two terms

x(5x + 13) + 2(5x + 13)

Factor out the common term; 5x + 13

6 0

4 years ago

Help help help help help

BaLLatris [955]

I gotta take a big śhit

4 0

3 years ago

I have to take a pic of the question

11111nata11111 [884]

ANSWER

$y=\frac{2}{3}x+\frac{4}{3}$

EXPLANATION

We want to find the equation of the straight line given on the graph.

The general form of a linear equation is given as:

$y=mx+b$

where m = slope; b = y-intercept

To find the slope, we apply the formula for slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

where (x1, y1) and (x2, y2) are two points on the line

Let us pick (1,2) and (4,4)

Therefore, the slope is:

$m=\frac{4-2}{4-1}=\frac{2}{3}$

To find the equation, we now apply the point-slope formula:

$y-y_1=m(x-x_1)$

Therefore, we have that the equation of the line is:

$\begin{gathered} y-2=\frac{2}{3}(x-1) \\ y-2=\frac{2}{3}x-\frac{2}{3} \\ y=\frac{2}{3}x-\frac{2}{3}+2 \\ y=\frac{2}{3}x+\frac{4}{3} \end{gathered}$

That is the equation of the line.

8 0

1 year ago