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Illusion [34]
3 years ago
9

Which triangles are congruent by ASA?

Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0
The second option ADV and EDA
MrRissso [65]3 years ago
3 0

Answer: ΔABE ≅ ΔDEA

Step-by-step explanation:

From the given picture, In Δ ACE we have AC= CE

Then, ∠A=∠E     (1)  [∵Angles opposite to equal angles of a triangle are equal.]      

Also, it is given that ∠B=∠D=90°    [Right angle]

Now, Consider ΔABE and ΔDEA

Here,

∠A=∠E      [From (1)]

AE=AE         [By Reflexive property]

∠B=∠D=90°   [given]

Then, by ASA congruence postulate , ΔABE ≅ ΔDEA

  • ASA postulate says that if two angles and the included side of one triangle are congruent to the corresponding two angles and the included side of other triangle, then the triangles are congruent.

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Answer:

a_{13}=2(13)+13=39

39 is the 13th term

Step-by-step explanation:

Okay so essentially the a_n is just a substitute for x.

See how in the equation they put n into the x spot:

y=mx+b\\a_n=mn+b\\a_n=2n+13

They changed the variable names:

y=a_n\\m=2\\n=x\\b=13

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When they say, 13 term, they mean a_{13} which would be the 13th answer in the series.  So the first term would be based off of a_1

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So whatever number is in the n position by a is what you'll be plugging into the x spot.

y=mx+b\\a_n=2n+13\\a_1=2(1)+13=15\\a_2=2(2)+13=17\\a_3=2(3)+13=19\\a_4=2(4)+13=21\\a_5=2(5) +13=23\\a_6=2(6)+13=25\\a_7=2(7)+13=27\\a_8=2(8) +13=29\\a_9=2(9)+13=31\\a_{10}=2(10)+13=33\\a_{11}=2(11)+13=35\\a_{12}=2(12)+13=37\\a_{13}=2(13)+13=39

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