Question

Line l1 passes through (-2, 5), and (-1, -10)

Answer 1

The equations of the lines l1 with points (-2, 5), and (-1, -10) and the line l2 with points (5, 15), and (3, 8), gives the coordinate of the intersection between the lines as the point; (-45/37, -250/37)

Which method can be used to describe the lines to find the intersection point?

The slope, m1, of line 1 l1 is found as follows;

• m1 = (5 - (-10))/(-2- (-1)) = -15

The equation of line l1 in point and slope form is therefore;

y1 - 5 = -15•(x - (-2))

Which gives;

y1 = -15•(x - (-2)) + 5 = -15•x - 25

• y1 = -15•x - 25

The slope, m2, of line 2 l2 is found as follows;

m2 = (15 - 8)/(5 - 3) = 3.5

Equation of line l2 is therefore;

y2 - 15 = 3.5•(x - 5)

Which gives;

y2 = 3.5•(x - 5) + 15 = 3.5•x - 2.5

• y2 = 3.5•x - 2.5

At the intersection point, we have;

y1 = y2

Therefore;

-15•x - 25 = 3.5•x - 2.5

18.5•x = -22.5

x = -22.5/18.5 = -45/37

y2 = 3.5•x - 2.5

At the intersection point, we have;

y = y2 = 3.5×(-22.5/18.5) - 2.5 = -250/37

y = -250/37

The coordinates of the intersection between the lines is therefore;

• (-45/37, -250/37)

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