Question

Twice the sum of 2 consecutive integers equals 106. determine the value of each integer

Answer 1

Hey there!!

Given word equation :

Let's take the first equation as ' x '

Then, the second number would be ' x + 1 '

Twice the sum of these = 106

Equation :

... 2 ( x + x + 1 ) = 106

... 2 ( 2x + 1 ) = 106

... 4x + 2 = 106

Subtract 2 on both sides

... 4x = 104

Divide by 4 on both sides

... x = 26

The first number= 26 and the second number = 27

The numbers are 26 and 27.

Hope my answer helps!

Answer 2

26&27

Start by writing out the equation which would be: 106=2(n+n+1)

N: fist integer
N+1: is the consecutive integer

Then solve:
106=2(2n+1). Combine.
106=4n+2. Distribute.
104=4n. Move whole numbers to the left.
N=26. Divide
N+1=27 Plug in for second integer