Twice the sum of 2 consecutive integers equals 106. determine the value of each integer
2 answers:
Hey there!!
Given word equation :
Let's take the first equation as ' x '
Then, the second number would be ' x + 1 '
Twice the sum of these = 106
Equation :
... 2 ( x + x + 1 ) = 106
... 2 ( 2x + 1 ) = 106
... 4x + 2 = 106
Subtract 2 on both sides
... 4x = 104
Divide by 4 on both sides
... x = 26
The first number= 26 and the second number = 27
The numbers are 26 and 27.
Hope my answer helps!
26&27
Start by writing out the equation which would be: 106=2(n+n+1)
N: fist integer
N+1: is the consecutive integer
Then solve:
106=2(2n+1). Combine.
106=4n+2. Distribute.
104=4n. Move whole numbers to the left.
N=26. Divide
N+1=27 Plug in for second integer
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