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Pani-rosa [81]
3 years ago
12

How do you solve these two equations? Please Help!!y = 2x + 160 y = - 3x + 208

Mathematics
1 answer:
Archy [21]3 years ago
6 0
Their are 2 main methods of solving 2 equations with 2 variables:
1) SUBSTITUTION
2) ELIMINATION
I'll show you both:

1) y = 2x + 160
y = - 3x + 208
plug what y is equal to in 1st equation into the y of the 2nd:
2x + 160 = -3x + 208
2x + 3x + 160 = -3x + 3x + 208
5x + 160 -160 = 208 - 160
5x = 48
5x/5 = 48/5
x = 48/5 = 9 3/5
now plug that x into either one of the original equations: y = -3x + 208 = -3(48/5) + 208
y = -144/5 + 208 = 1040/5 - 144/5 = 896/5
y = 179 1/5

2) add the whole equations together so as to cancel out one of the variables:
I'm choosing to eliminate the y, so we need y-y to remove the y's, I'll multiply the whole 2nd equation by -1 to make that -y
-1 (y = - 3x + 208)
-y = 3x - 208
So set it up like:
y = 2x + 160
-[y = 3x - 208]
---------------------
0 = 5x - 48
0+48 = 5x -48 +48
5x = 48
5x/5 = 48/5
x = 48/5
plug that x value into one of the original equations: y = 2x + 160 = 2(48/5) + 160
y = 96/5 + 160 = 96/5 + 800/5 = 896/5
y = 179 1/5

SO WE GOT THE SAME VALUES BOTH WAYS.
WHEN YOU SEE FUTURE PROBLEMS LIKE THESE, SOME WILL BE QUICKER BY ELIMINATION AND OTHERS BY SUBSTITUTION

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A player shoots a basketball from a height of 6 feet. The equation, h = -16t^2 + 25t + 6, gives the height, h , of the basketbal
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Answer:

\boxed {\boxed {\sf 7.5 \ feet}}

Step-by-step explanation:

We are given this function for the height (h) after t seconds:

h=-16t^2+25t+6

Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.

h= -16(1.5)^2+25(1.5)+6

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponent first.

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h= -16(2.25)+25(1.5)+6

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h= -36+25(1.5)+6

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Add.

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This is already rounded to the nearest tenth, so it is the answer.

After 1.5 seconds, the basketball is at a height of 7.5 feet.

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3 years ago
Add. (5y - 1) + (-2y + 4) A) 3y - 5 B) 3y + 3 C) 7y + 3 D) 7y - 3
Ivan
(5y - 1) + (-2y + 4)  = 5y - 1 - 2y + 4
                              = 5y - 2y - 1 + 4
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