Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.
IQ scores of at least 130.81 are identified with the upper 2%.
The average rate of change in a function from a to b is
.
For the left function, from x = 4 to x = 5, the rate of change is
.
For the right function, the rate of change is
Using a ratio to compare the right function's growth rate with that of the left function, you get .
The right function is growing approximately 21 times faster than the left function (over the interval from 4 to 5).
Answer:
1 hotdog is $3.5.
1 drink is $2.
Step-by-step explanation:
18.50= 3x+4y(times 5)
25.50=5x+4y(times -3)
92.5=15x+20x
-76.5=-15x+-12y
16=-8y
2=y
18.50=3x+4(2)
10.50=3x+8
10.50=3x
3.5=x
Answer:
Given - Two angles measures 2x and 3x
To find - size of 3x
Solution -
2x + 3x = 360° ( Make reflex angle )
5x = 360°
x = 360/5
x = 72°
3x = 3 * 72 = 216°