2(y+1) = 3 LCD is 4
2*y + 2*1 = 3
2y + 2 = 3
2y = 3 - 2
2y = 1
y = 1 / 2
X 7 9 11 13 y -1 2 5 8 Is the relationship linear, exponential, or neither
2 answers:
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2(y+1) = 3 LCD is 4
2*y + 2*1 = 3
2y + 2 = 3
2y = 3 - 2
2y = 1
y = 1 / 2
Answer:
The correct option is D. y = 25.
Step-by-step explanation:
i) From the table and our own observation and a trial and error approach we
can clearly see that the equation that matches y in feet ( the distance
traveled by the rocket) and x in seconds ( the time elapsed) is given by the
equation y = 25
Therefore the correct option is D. y = 25.