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love history [14]

4 years ago

14

What's an example of a situation in which it is better to find the difference in order to compare two quantities.

1 answer:

Flauer [41]4 years ago

3 0

When you find the difference to compare two different quantities, it shows what is missing from one that is in the other. for example if you compare 4 and 8 by subtracting 4 from 8, then you know that 8 is 4 more than 4.

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Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

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$f(x,y,z)=2z^2x+y^3$

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Read 2 more answers

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the

Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be $x.$

And the hotel charge in second city before tax be $y.$

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

$y=x-1500$ ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of $x$ + 10% of $y$ = $670.

$\frac{6x}{100} +\frac{10y}{100} =670$

$0.06x+0.10y=670$

Substituting the value of $y$ from equation (1) we get:

$0.06x+0.10(x-1500)=670$

$0.06x+0.10x-150=670$

$0.16x-150=670$

<em>Adding both sides by 150 we get:</em>

$0.16x=820$

<em>Dividing both sides by 0.16 we get:</em>

$x=5125.$

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of $x$ in equation (1) we get:

$y=x-1500$

$y=5125-1500$

$y=3625.$

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0

4 years ago