Answer:
(-infinity, infinity)
Step-by-step explanation:
I assume it's y = 2x-6 which is a linear function. The line goes on forever.
Volume of cone= 1/3πr^2h
8842.24 m^3= 1/3πr^2h
1/3*3.14*33*r^2= 8842.24m^3
r^2 = 8842.24*3/3.14*33
r^2= 26526.72/103.62
r^2 = 256
r= √256
r= 16m
Hope it helps. Please mark brainliest.
That's true.
That will make the thing a third of its original size.
Answer:
it takes 48 days for 15 men to work
it takes 16 days for 15/48*16
the answer is 5 men
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
</span><span>
</span>
