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2 years ago

10

Explain one way to find the height of a trapezoid if you know the area of the trapezoid and the length of both bases.

1 answer:

skelet666 [1.2K]2 years ago

8 0

1) Add the length of both bases: [ Total Length = Length 1 + Length 2 ]

2) Divide the length that you found by 2. [ Average Length = Total Length ÷ 2 ]

3) Divide the Area with the length found [ Height = Area ÷ average length ]

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In trying to calculate the product of 5 and 12 in her head, Evie first multiplied 5 times 10 and then added the result to the pr

Pie

Answer:

Step-by-step explanation:

distributive

7 0

3 years ago

Solve the following system

scZoUnD [109]

Answer:

{x = -4 , y = 2 , z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = -4 , y = 2 , z = 1

4 0

2 years ago

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

7 0

2 years ago

YP_2021_Math 8_Progress Monitor_02

Lisa [10]

(4,4).........................

7 0

2 years ago

Paul has an eight-year loan with a principal of $26,900. The loan has an interest rate of 8.18%, compounded quarterly. If Paul p

babymother [125]

Answer:

The answer is "option b"

Step-by-step explanation:

Amount = $26,900

r= 0.0818 %

$i=\frac{r}{4}\\\\$

$=\frac{0.0818}{4}\\\\=0.02045$

t= 8 years

$n= 8 \times 4$

$=32$

$D=\frac{1-(1+i)^{-n}}{i}\\$

$=\frac{1-(1+0.02045)^{-32}}{0.02045}\\\\=\frac{1-(1.02045)^{-32}}{0.02045}\\\\=\frac{1-0.52319627}{0.02045}\\\\=\frac{0.47680373}{0.02045}\\\\=23.3155858$

$Q= \frac{Amount}{Discount \ factor }\\$

$=\frac{26900}{23.3155858} \\\\=1153.73468$

Payment $=1153.73468 \times 32\\\\$

$= \$ 36919.5098\\$

$\text{Total interest = Payment - amount}$

$= \$ 36919.5098 - \$ 26900 \\\\ = \$ 10019.5098$

$\text{Finance charge = Total interest + service charge}$

$= \$ 10019.5098 + \$ 1527\\\\ = \$ 11546.5098$

3 0

3 years ago