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Maslowich
2 years ago
11

Sorry can someone help please…

Mathematics
1 answer:
BartSMP [9]2 years ago
3 0
25) -4
26) -8
27) 0
28) -7
29)6
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Mitzi has 79 coins she divides the coins equally among herself and her 3 brothers Mitzi will keep any coins left over how many c
Elanso [62]

Answer:

19

Step-by-step explanation:

79÷4=19R3

       ≈ 19

7 0
2 years ago
What is the greatest common factor of 6a²b3 + 15ab^5– 9a^3b^2??
Roman55 [17]

Answer:

3ab^2

Step-by-step explanation:

Factor 6a^2b^3

= 2 * 3 * a * a * b * b * b

Factor 15ab^5

= 3 * 5 * a * b * b * b * b * b

Factor 9a^3b^2

3 * 3 * a * a * a * b * b

Common Factor

= 3 * a * b * b

Simplify

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2 years ago
Simplify in Exponential form <br> First correct answer gets BRAINLIEST
svlad2 [7]

Answer:

Steps to simplifying fractions

Therefore, 9/9 simplified to lowest terms is 1/1.

Reduce 9/8 to lowest terms

9/8 is already in the simplest form. It can be written as 1.125 in decimal form (rounded to 6 decimal places).Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the measure of ∠ 7.<br><br> Given:<br> ∠1 is a right angle<br> ∠3 = 37°<br> ∠8 = 62°
Bess [88]

Answer:

<h2>-28°</h2>

Step-by-step explanation:

It is given that ∠1 is a right angle that is ∠1 = 90°.

∠8 - ∠1 = ∠ 7 = 62° - 90° = - 28°.

7 0
3 years ago
A popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags
ELEN [110]

Answer:

Step-by-step explanation:

Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.

i.e. Sample mean = 1040 and

Sample std dev s = 25 gm

Sample size n = 100

Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm

\bar X = N(1040,25)

Normal curve would be with mean 1040 and std deviatin 25

b) P(X>1115)

= 1-0.9987

=0.0013

i.e. 0.13% would receive a bag that had a weight greater than 1115 grams

8 0
3 years ago
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