1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maslowich
3 years ago
11

Sorry can someone help please…

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0
25) -4
26) -8
27) 0
28) -7
29)6
You might be interested in
I’m not quite sure how to solve this any help would work!
Gnoma [55]

Answer:

11. O = (-1, 5/2); 12. H = (1,4)  

Step-by-step explanation:

11. Circumcentre

Your points form the vertices of a right triangle (see image below).

The circumcentre (O) of a right triangle must be at the midpoint of the hypotenuse.

Your hypotenuse has the ends at (-3,4) and (1,1), so

O = ((-3 + 1)/2),(4 + 1)/2))

O = (-2/2,5/2)

O = (-1, 5/2)

===============

12. Orthocentre

The orthocentre (H) of a right triangle is the vertex at the right angle.

Your right angle is at (1, 4), so

H= (1,4)

3 0
3 years ago
True or false? ( help me please and thank you)
Dmitriy789 [7]

Answer:

False

Step-by-step explanation:

Well it's True in a way, but they didn't simplify all the way. Correct simplification would be 1/3

4 0
3 years ago
Read 2 more answers
A stack of 10 different cards are shuffled and spread out face down. If 3 cards are turned face up, how many different 3-card co
Advocard [28]

Answer:

<h3>120 different ways</h3>

Step-by-step explanation:

Using the combination formula as shown;

nCr = n!/(n-r)!r!

If a stack of 10 different cards are shuffled and spread out face down. If 3 cards are turned face up, the number of different ways 3cards combinations are possible is expressed as;

10C3 = 10!/(10-3)!3!

10C3 = 10!/(7)!3!

10C3 = 10*9*8*7!/7!*3*2

10C3 = 10*9*8/3*2

10C3 = 720/6

10C3 = 120 different ways

Hence there are 120 different card combinations

5 0
3 years ago
Marco and his two younger sisters would like to purchase a silver charm bracelet for their mother’s birthday. They went to the m
mr Goodwill [35]
Given:
Cost of bracelet without charm - $85
cost of each charm - $15

Function notation: f(x) = 15x + 85

The price of the bracelet depends on the number of charms they will buy. x represents the number of charms they will buy. 

The reasonable domain for this function is at least 1. They must buy at least 1 charm because they intend to buy their mom a silver charm bracelet.

If their budget is 250

250 = 15x + 85
250 - 85 = 15x
165 = 15x
165/15 = x
 11 = x

They can buy at most 11 charms without going beyond their budget.


4 0
3 years ago
Solve the inequality -4x + 5 &gt; 21​
nordsb [41]

Answer:

x < -4

Step-by-step explanation:

Step 1: Write inequality

-4x + 5 > 21

Step 2: Solve for <em>x</em>

  1. <u>Subtract 5 on both sides:</u> -4x > 16
  2. <u>Divide both sides by -4:</u> x < -4
4 0
4 years ago
Read 2 more answers
Other questions:
  • Mark wants to know how many families in his neighborhood plan to attend the neighborhood party. He puts all 80 of the neighborho
    5·2 answers
  • If you pass a road test, you will get your drivers license. Tamara passed her road test
    11·1 answer
  • A can holds 2 gallons of paint how many cans can we fill with 11 gallons of paint
    15·2 answers
  • you had 21$ to spend on 7 raffle tickets. After buying them you had 0$. How much did each raffle ticket cost?
    12·2 answers
  • Ms. Smith bought a 6 pound bag of candy for her students. She gave away 3 pounds and ate 10 ounces of candy. How many ounces doe
    15·2 answers
  • Which of the tables represents a function? Table A, Table B, Table C, Table D​
    6·1 answer
  • Simplify this expression 3(3e+2f)+4f+2
    14·1 answer
  • EXPLAIN HOW TO FIND THE AREA OF THE<br> SHADED Region.
    5·1 answer
  • A wheelchair ramp is being built for entrance to a portable classroom. If the ramp has a slope of
    9·2 answers
  • Can someone help with dis plz :/
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!