Please help me with the geometry.

Mathematics

1 answer:

Fynjy0 [20]2 years ago

8 0

Step-by-step Answer:

To prove

Triangle ADC is congruent to triangle BDC

AC=BC (given)

DC=DC (common)

AD=BD (given CD bisects AB)

Therefore triangle ACD is congruent to BDC (justification: SSS)

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5x+y=-10 4x-7y=-8 Substition Method (Show it step by step please!)

Fynjy0 [20]

$\left\{\begin{array}{ccc}5x+y=-10&|\text{subtract 5x from both sides}\\4x-7y=-8\end{array}\right\\\left\{\begin{array}{ccc}y=-5x-10&|\text{substitute to the second equation}\\4x-7y=-8\end{array}\right\\\\4x-7(-5x-10)=-8\qquad\text{use distributive property}\\\\4x+(-7)(-5x)+(-7)(-10)=-8\\\\4x+35x+70=-8\qquad\text{subtract 70 from both sides}\\\\39x=-78\qquad\text{divide both sides by 39}\\\\\boxed{x=-2}\\\\\text{Put the value of x to the first equation}\\\\y=-5(-2)-10\\\\y=10-10\\\\\boxed{y=0}$