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GuDViN [60]
3 years ago
6

Please help me with the geometry.

Mathematics
1 answer:
Fynjy0 [20]3 years ago
8 0

Step-by-step Answer:

To prove

Triangle ADC is congruent to triangle BDC

AC=BC  (given)

DC=DC  (common)

AD=BD (given CD bisects AB)

Therefore triangle ACD is congruent to BDC  (justification: SSS)

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Triangle VXW is similar to triangle ZXY. Triangle V X W. Side V W is 12 miles and side V X is 14 miles. Triangle Z X Y. Side Y Z
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Answer: Kara should have written the proportion in step 1 as;

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Triangle VXW with side VW = 12 and side VX = 14. Also Triangle ZXY with side YZ = 72 and side XZ = x.

For two triangles to be similar, then there must be a similarity ration that is consistent with all sides in both triangles. This means if in the first triangle a side measures  1 unit and the similar side in the other triangle measures 5 units, then the ratio of similarity of corresponding sides shall be ratio 1 : 5. So for every corresponding side in the second triangle the measurement shall be times five of the side that corresponds in the first triangle.

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What Kara did was as follows;

VX/ZY = VW/ZX

Which translates to 14/72 = 12/x

This was a wrong calculation because the side that corresponds to VX is ZX and not ZY.

The correct step should therefore have been;

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<em />

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