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4 years ago

Can somebody help me with number 8?

Mathematics

1 answer:

iVinArrow [24]4 years ago

8 0

Yes, it is a rational number. This is because rational numbers are any number that can be expressed as a fraction where the numerator and denominators are whole numbers. 13/3 does not need to be expressed as a decimal for you to know this.

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Complete the following statement. Round to the nearest hundredth .

RSB [31]

f(x) = 3/(x + 2) - √x - 3

f(7) = 3/(7 + 2) - √7 - 3

f(7) = 3/9 - √4

f(7) = 0.333 - 2

f(7) = -1.67

7 0

3 years ago

The figure shows two triangles on a coordinate grid:

svet-max [94.6K]

Answer:

Whats up good luck... sorry my answer didnt submit

Step-by-stp explanation:

4 0

3 years ago

Determine whether 5, 226 is divisible by 2,3,4,5,6,9, or 10.

uranmaximum [27]

Answer:

2,3,6

Step-by-step explanation:

5,226 ...(1)

unit digit=6

6 is divisible by 2,

so (1) is divisible by 2.

last two digits=26 ,not divisible by 4,

so (1) is not divisible by 4.

5+2+2+6=15 divisible by 3 but not divisible by 9.

so (1) is divisible by 3 but not divisible by 9.

2×3=6,so (1) is divisible by 6.

unit digit=6≠0 or 5

so (1) is not divisible by 5 or 10.

8 0

3 years ago

Read 2 more answers

annie adds 2 spoonfuls of sugar to her tea and sophie adds 3 spoonfuls to her tea. If one spoonful is 4 grams of sugar and a a c

Tresset [83]

240%

Step-by-step explanation:

if there is 240 grams then you just put a percent sing but are you asking What is the percentage of sugar in each cup? by spoons?

3 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$