X×y^3×xy = x^2×y^4f final answer
Answer:
Discontinuity at (-4,-2), zero at (-2,0).
Step-by-step explanation:
We are given that a function

We have to find the discontinuity and zero of the given function.
Discontinuity: It is that point where the function is not defined.
It makes the function infinite.


When x=-4 then
It is indeterminate form
Function is not defined
After cancel out x+4 in numerator and denominator then we get

Substitute x=-4

Therefore, the point of discontinuity is (-4,-2).
Zero: The zero of the function is that number when substitute it in the given function then the function becomes zero.
When substitute x=-2
Then , 
The function is zero at (-2,0).
Hence, option C is true.
4
)
10(x+6)+8(x−3)=5(5x−4)
2 Expand.
10
x
+
60
+
8
x
−
24
=
25
x
−
20
10x+60+8x−24=25x−20
3 Simplify
10
x
+
60
+
8
x
−
24
10x+60+8x−24 to
18
x
+
36
18x+36.
18
x
+
36
=
25
x
−
20
18x+36=25x−20
4 Subtract
18
x
18x from both sides.
36
=
25
x
−
20
−
18
x
36=25x−20−18x
5 Simplify
25
x
−
20
−
18
x
25x−20−18x to
7
x
−
20
7x−20.
36
=
7
x
−
20
36=7x−20
6 Add
20
20 to both sides.
36
+
20
=
7
x
36+20=7x
7 Simplify
36
+
20
36+20 to
56
56.
56
=
7
x
56=7x
8 Divide both sides by
7
7.
56
7
=
x
7
56
=x
9 Simplify
56
7
7
56
to
8
8.
8
=
x
8=x
10 Switch sides.
x
=
8
x=8
Your answer is
X=8
Answer:
ans is behind it
Step-by-step explanation:
hope it helps uh