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3 years ago

Find the value of x. A) 21 B) 27 C) 31 D) 34

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

The 2 angles given are vertical angles, which mean they are the same.

So we have: 3x +1 = 64

Subtract 1 from each side:

3x = 63

Divide both sides by 3:

X = 63 / 3

X = 21

The answer is A.

tamaranim1 [39]3 years ago

4 0

A. 64=(3x+1)
subtract one from both sides and then divide by 3

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Find the product: − 3/5 (− 14/9 )

zlopas [31]

Answer:

Step-by-step explanation:

distributive property: a(b+c)=ab+ac

product it's must be multiply the numbers, fractions, factors, and multiples.

3/5*14/9

you can also cross out the common factor of 3.

1/5*14/3

multiply the fractions.

1*14/5*3

1*14=14

14/5*3

5*3=15

Hope this helps!

Thanks!

5 0

3 years ago

Plssss help i just cant figure it out

mariarad [96]

It is just two as you are dividing a negative by and negative turns into a positive

8 0

3 years ago

The mean weight of the seven linebackers was 236 pounds. The first six linebackers weighed 215lb, 305lb, 265lb, 196lb, 221lb, an

Nadya [2.5K]

Answer:

The weight of the seventh linebacker is = 214 lb.

Step-by-step explanation:

Given:

Mean of 7 linebackers = 236 lb

The weights of first 6 linebackers are:

215 lb, 305 lb, 265 lb, 196 lb, 221 lb and 236 lb

To find the weight of seventh linebacker.

Solution:

Let the weight of the seventh linebacker be = $x$

The mean of 7 line backers will be given as:

⇒ $\frac{215+305+265+196+221+236+x}{7}$

The mean of the 7 linebackers is given = 236 lb

Thus, the equation to find $x$ will be :

$\frac{215+305+265+196+221+236+x}{7}=236$

Simplifying.

$\frac{1438+x}{7}=236$

Multiplying both sides by 7.

$7.\frac{1438+x}{7}=236(7)$

$1438+x=1652$

Subtracting both sides by 1438.

$1438-1438+x=1652-1438$

∴ $x=214$

Thus, the weight of the seventh linebacker is = 214 lb.

7 0

3 years ago

Simplify -2(x + 4)^2 – 3 + 5x

RoseWind [281]

Answer:

-2x^2-11x-35 hope this helps

Step-by-step explanation:

3 0

3 years ago

If a triangle has sides that are 21 and 6 what is the range for third side x?

VikaD [51]

Answer:

15<x<27

Step-by-step explanation:

Rule for the sides of a triangle:

The sum of the two smallest sides of a triangle must be greater than the biggest side.

In this question:

Sides of 6, 21 and x. We have to find the range for x.

If 21 is the largest side:

Two smallest are 6 and x.

x + 6 > 21

x > 21 - 6

x > 15

If x is the largest side:

Two smallest and 6 and 21. So

21 + 6 > x

27 > x

x < 27

Then

x has to be greater than 15 and smaller than 27. So the answer is:

15<x<27

8 0

3 years ago