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evablogger [386]
3 years ago
11

If a triangle has sides that are 21 and 6 what is the range for third side x?

Mathematics
1 answer:
VikaD [51]3 years ago
8 0

Answer:

15<x<27

Step-by-step explanation:

Rule for the sides of a triangle:

The sum of the two smallest sides of a triangle must be greater than the biggest side.

In this question:

Sides of 6, 21 and x. We have to find the range for x.

If 21 is the largest side:

Two smallest are 6 and x.

x + 6 > 21

x > 21 - 6

x > 15

If x is the largest side:

Two smallest and 6 and 21. So

21 + 6 > x

27 > x

x < 27

Then

x has to be greater than 15 and smaller than 27. So the answer is:

15<x<27

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Is 3,540 reasonable for the difference 9,760-5,220
Ugo [173]

Answer:

no it's 4540

Step-by-step explanation:

you just subtract 5220 from 9760 and you get your difference

3 0
3 years ago
Q2 - With decimals
Mila [183]

Answer:

Simplify the following algebraic expressions.

- 6x + 5 + 12x -6

2(x - 9) + 6(-x + 2) + 4x

3x2 + 12 + 9x - 20 + 6x2 - x

(x + 2)(x + 4) + (x + 5)(-x - 1)

1.2(x - 9) - 2.3(x + 4)

(x2y)(xy2)

(-x2y2)(xy2)

Solution

Group like terms and simplify.

- 6x + 5 + 12x -6 = (- 6x + 12x) + (5 - by

Solution

Use rules of exponential to simplify the numerator first.

(a b2)(a3 b) / (a2 b3) = (a4 b3) / (a2 b3)

Rewrite as follows.

(a4 / a2) (b3 / b3)

Use rule of quotient of exponentials to simplify.

= a2

Rewrite as follows.

(21 x5) / (3 x4) = (21 / 3)(x5 / x4)

Simplify.

= 7 x

(6 x4)(4 y2) / [ (3 x2)(16 y) ]

Multiply terms in numerator and denominator and simplify.

(6 x4)(4 y2) / [ (3 x2)(16 y) ] = (24 x4 y2) / (48 x2 y)

Rewrite as follows.

= (24 / 48)(x4 / x2)(y2 / y)

Simplify.

= (1 / 2) x2 y

Factor 4 out in the numerator.

(4x - 12) / 4 = 4(x - 3) / 4

Simplify.

= x - 3

Factor -5 out in the numerator.

(-5x - 10) / (x + 2) = - 5 (x + 2) / (x + 2)

Simplify.

= - 5

Factor numerator and denominator as follows.

(x2 - 4x - 12) / (x2 - 2x - 24) = [(x - 6)(x + 2)] / [(x - 6)(x + 4)]

Simplify.

= (x + 2) / (x + 4) , for all x not equal to 6

Solve for x the following linear equations.

2x = 6

6x - 8 = 4x + 4

4(x - 2) = 2(x + 3) + 7

0.1 x - 1.6 = 0.2 x + 2.3

- x / 5 = 2

(x - 4) / (- 6) = 3

(-3x + 1) / (x - 2) = -3

x / 5 + (x - 1) / 3 = 1/5

Solution

Divide both sides of the equation by 2 and simplify.

2x / 2 = 6 / 2

x = 3

Add 8 to both sides and group like terms.

6x - 8 + 8 = 4x + 4 + 8

6x = 4x + 12

Add - 4x to both sides and group like terms.

6x - 4x = 4x + 12 - 4x

2x = 12

Divide both sides by 2 and simplify.

x = 6

Expand brackets.

4x - 8 = 2x + 6 + 7

Add 8 to both sides and group like terms.

4x - 8 + 8 = 2x + 6 + 7 + 8

4x = 2x + 21

Add - 2x to both sides and group like terms.

4x - 2x = 2x + 21 - 2x

2x = 21

Divide both sides by 2.

x = 21 / 2

Add 1.6 to both sides and simplify.

0.1 x - 1.6 = 0.2 x + 2.3

0.1 x - 1.6 + 1.6 = 0.2 x + 2.3 + 1.6

0.1 x = 0.2 x + 3.9

Add - 0.2 x to both sides and simplify.

0.1 x - 0.2 x = 0.2 x + 3.9 - 0.2 x

- 0.1 x = 3.9

Divide both sides by - 0.1 and simplify.

x = - 39

Multiply both sides by - 5 and simplify.

- 5(- x / 5) = - 5(2

What is the y intercept of the line - 4 x + 6 y = - 12?

Solution

Set x = 0 in the equation and solve for y.

- 4 (0) + 6 y = - 12

6 y = - 12

y = - 2

y intercept: (0 , - 2)

What is the x intercept of the line - 3 x + y = 3?

Solution

Set y = 0 in the equation and solve for x.

- 3 x + 0 = 3

x = -1

x intercept: (-1 , 0)

What is point of intersection of the lines x - y = 3 and - 5 x - 2 y = - 22?

Solution

A point of intersection of two lines is solution to the equations of both lines. To find the point of intersection of the two lines, we need to solve the system of equations x - y = 3 and -5 x - 2 y = -22 simultaneously. Equation x - y = 3 can be solved for x to give

x = 3 + y

Substitute x by 3 + y in the equation - 5 x - 2 y = -22 and solve for y

-5 (3 + y) - 2 y = - 22

-15 - 5 y - 2 y = - 22

-7 y = - 22 + 15

-7 y = - 7

y = 1

Substitute x by 3 + y in the equation -5 x - 2 y = - 22 and solve for y

x = 3 + y = 3 + 1 = 4

Point of intersection: (4 , 1)

For what value of the constant k does the line - 4 x + k y = 2 pass through the point (2,-3)?

Solution

For the line to pass through the point (2,-3), the ordered pair (2,-3) must be a solution to the equation of the line. We substitute x by 2 abd y by - 3 in the equation.

- 4(2) + k(-3) = 2

Solve the for k to obtain

k = - 10 / 3

What is the slope of the line with equation y - 4 = 10?

Solution

Write the given equation in slope intercept form y = m x + b and identify the slope m.

y = 14

It is a horizontal line and therefore the slope is equal to 0.

What is the slope of the line with equation 2 x = -8?

Solution

The above equation may be written as

x = - 4

It is a vertical line and therefore the slope is undefined.

Find the x and y intercepts of the line with equation x = - 3?

Solution

The above is a vertical line with x intercept only given by

(-3 , 0)

Find the x and y intercepts of the line with equation 3 y - 6 = 3?

Solution

The given equation may be written as

y = 3

The above is a horizontal line with y intercept only given by

(0 , 3)

What is the slope of a line parallel to the x axis?

Solution

A line parallel to the x axis is a horizontal line and its slope is equal to 0.

What is the slope of a line perpendicular to the x axis?

Solution

A line perpendicular to the x axis is a vertical line and its slope is undefined

Step-by-step explanation:

y = -22 and solve for y

-5 (3 + y) - 2 y = - 22

-15 - 5 y - 2 y = - 22

-7 y = - 22 + 15

-7 y = - 7

y = 1

8 0
3 years ago
I need help pls i would really appreciate it !!
vlabodo [156]
Answer : a
Sin is opposite/hypotenuse which is 8/10
And this is 4/5
3 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, THANK YOU!
bixtya [17]

Answer:

\sqrt{37}

Step-by-step explanation:

To find the distance between a point (m, n ) and the line

Ax + By + C = 0

d = \frac{|Am +Bn+C|}{\sqrt{A^2+B^2} }

Here (m, n) = (6, 2) and rearranging the line

6x - y + 3 = 0 ← in general form

with A = 6, B = - 1 and C = 3 , then

d = \frac{|6(6)-1(2)+3|}{\sqrt{6^2+(-1)^2} }

   = \frac{|36-2+3|}{\sqrt{36+1} }

   = \frac{37}{\sqrt{37} }  

Rationalise the denominator by multiplying numerator/ denominator by \sqrt{37}

= \frac{37}{\sqrt{37} } × \frac{\sqrt{37} }{\sqrt{37} }

=\frac{37\sqrt{37} }{37} ← cancel 37 on numerator/ denominator

= \sqrt{37}

5 0
3 years ago
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irga5000 [103]
For the first one is has greater then 3 terms
The middle one is has exactly one term
And the last one is has two terms
I believe I hope this helps
4 0
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