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3 years ago

If a triangle has sides that are 21 and 6 what is the range for third side x?

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Answer:

15<x<27

Step-by-step explanation:

Rule for the sides of a triangle:

The sum of the two smallest sides of a triangle must be greater than the biggest side.

In this question:

Sides of 6, 21 and x. We have to find the range for x.

If 21 is the largest side:

Two smallest are 6 and x.

x + 6 > 21

x > 21 - 6

x > 15

If x is the largest side:

Two smallest and 6 and 21. So

21 + 6 > x

27 > x

x < 27

Then

x has to be greater than 15 and smaller than 27. So the answer is:

15<x<27

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3 years ago

The equation for a parabola has the form y = ax2 + bx + c, where a, b, and c are constants and a ≠ 0. find an equation for the p

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3 years ago

The length of a rectangle is 4 inches more than its width, and its perimeter is 34 inches. Find the length and width of the

gizmo_the_mogwai [7]

Answer:

Width = 6.5 inches

Length = 10.5 inches

Step-by-step explanation:

Let

"l" be length of rectangle

and

"w" be width of rectangle

Since length of rectangle is 4 inches MORE THAN WIDTH, we can write:

l = 4 + w

The perimeter is sum of all sides, so

Perimeter = l + l + w + w = 2l + 2w

The perimeter is 34, so we can write:

2l + 2w = 34

Putting 1st equation in 2nd, we get equation in "w" and solve for this first:

$2l + 2w = 34\\2(4+w) + 2w = 34\\8+2w+2w=34\\4w=26\\w=\frac{26}{4}=6.5$

Width is 6.5 in

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3 years ago