Answer:
The second city is 54 miles behind the first city
Step-by-step explanation:
The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.
The speed of the second bus is then 54/0.6 = 90 mph
When 1 and a half hour has passed, the first bus has moved a distance of
= 81 miles
The second bus (behind the first bus) has moved
= 135 miles
The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city
So, the second city is 54 miles behind the first city
Answer:
Why are you timesing me IDK
Step-by-step explanation:
Answer:
6x−7
Step-by-step explanation:
2x−7+4x
=2x+−7+4x
Combine Like Terms:
=2x+−7+4x
=(2x+4x)+(−7)
=6x+−7
Answer:
I think it's 3:5
Step-by-step explanation:
I really don't understand your question
Answer:
15/18, 0.84, 85%
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)