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3 years ago

Which point is closer to the x axis

Mathematics

1 answer:

posledela3 years ago

5 0

there's no graph but the x axis is horizontal so look for the point closest to the horizontal line

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Convert 62.4lb/ft^3 to kg/m^3

melamori03 [73]

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3 years ago

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mafiozo [28]

Answer:

58°

Step-by-step explanation:

in ΔABD

∠ADB = 32°

∠DBA = 90°

∠BAD = 180° - (32 + 90)

∠BAD = 58°

As ΔBAD ≅ ΔBCD

∠BAD = ∠BCD

So ∠BCD = 58°

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3 years ago

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Which algebraic expression is equivalent to the expression below? 6x+15y A. 3(2x - 5y) B. 3(5x - 2y) C. 3(2x + 5y) D. 3(5x + 2y)

Marina CMI [18]

Answer:

C. 3(2x + 5y) is the algebraic expression equivalent to the expression

Step-by-step explanation:

From the question, the given expression is 6x + 15y.

Factorizing this expression gives 3(2x + 5y). Hence, the algebraic expression equivalent to the expression 6x + 15y is 3(2x + 5y). (Option C).

Checking the remaining options

A. 3(2x - 5y)

Expanding this gives 6x - 15y. It is not equivalent to the given expression

B. 3(5x - 2y)

Expanding this gives 15x - 6y. It is not equivalent to the given expression

D. 3(5x + 2y)

Expanding this gives 15x + 3y. It is not equivalent to the given expression.

Hence, C. 3(2x + 5y) is the algebraic expression equivalent to the expression.

3 0

3 years ago

Jill has 60 ribbons. Half of them are red. The rest are blue and black. There are 4 more blue ribbons than black ribbons. how ma

Molodets [167]

Answer:

Step-by-step explanation:

3 0

3 years ago

A chemical plant has an emergency alarm system. When an emergency situation exists, the alarm sounds with probability 0.95. When

Lapatulllka [165]

Answer:

6.56% probability that a real emergency situation exists.

Step-by-step explanation:

We have these following probabilities:

A 0.4% probability that a real emergency situation exists.

A 99.6% probability that a real emergency situation does not exist.

If an emergency situation exists, a 95% probability that the alarm sounds.

If an emergency situation does not exist, a 2% probability that the alarm sounds.

The problem can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem:

What is the probability of a real emergency situation existing, given that the alarm has sounded.

P(B) is the probability of there being a real emergency situation. So $P(B) = 0.004$ .

P(A/B) is the probability of the alarm sounding when there is a real emergency situation. So P(A/B) = 0.95.

P(A) is the probability of the alarm sounding. This is 95% of 0.4%(real emergency situation) and 2% of 99.6%(no real emergency situation). So

P(A) = 0.95*0.04 + 0.02*0.996 = 0.05792

Given that the alarm has just sounded, what is the probability that a real emergency situation exists?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.004*0.95}{0.05792} = 0.0656$

6.56% probability that a real emergency situation exists.

6 0

3 years ago