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xenn [34]
3 years ago
6

Often when a family member is dying, the client and the family are at different stages of grieving. during which stage of a clie

nt's grieving is the family likely to require more emotional nursing care than the client?
Biology
1 answer:
Semenov [28]3 years ago
3 0
Often when a family member is dying, the client and the family are at different stages of grieving. During which stage of a client's grieving is the family likely to require more emotional nursing care than the client?

1. Anger

2.Denial

3.Depression

4.Acceptance

(The ANSWER is #No.4)

In the stage of acceptance, the client frequently detaches from the environment and may become indifferent to family members. In addition, the family may take longer to accept the inevitable death than does the client. Although the family may not understand the anger, dealing with the resultant behavior may serve as a diversion. Denial often is exhibited by the client and family members at the same time. During depression, the family often is able to offer emotional support, which meets their needs.
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Answer:

The technology that allows scientists to study the activity of many genes at once is a <u>microarray</u>.

Explanation:

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Solution :

Red is dominant over the white leaves and pointed is dominant over smooth.

Red = R ,    white = r

Pointed = P ,   smooth = p

Red, pointed x white,smooth ------ Parents

RRPP                 rrpp

RP                      rp  ----------------- Gametes

         RrPp    -------- $F_1$

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When this $F_1$ is test crossed,

RrPp  x  rrpp     ----  $F_1$ test cross

Gametes   → rp

RP ---------- RrPp - red, pointed - 36 parental type

Rp ---------- Rprp - red, smooth - 14 re- combination

rP ----------- rrPp - white pointed - 10 re- combination

rp ----------- rrpp - white, smooth - 40 - parental type

                                    Total =   100

As this ratio is deviating from 1:1:1:1, it indicated the two genes are linked.

Linkage strength = percentage of crossing over = map distance between the genes.

Percentage crossing = recombination frequency = percentage of recombination.

Recombination frequency $=\frac{\text{total no. of recombination}}{\text{total no. of progeny}}\times 100$

                                         $=\frac{14+10}{100} \times 100$

                                         = 24 %

                                        = 24 map units

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