3. List all the coefficients and constants

Write sin 75° in terms of the cosine

timama [110]

Answer:

Use z = a +bi = IzI (cos (Ф) + i sin (Ф)) to find the trigonometric form. √2+∛ / 2 (cos (0) + i sin (0))

Step-by-step explanation:

3 0

3 years ago

GHJK is a square with diagonals intersecting at L. Given that GH=2 and GL=square root of , complete the statement

Dafna11 [192]

Answer:

GL = square root of 2 = √2

Step-by-step explanation:

Given: GHJK is a square and its diagonals intersect at L

GJ and HK are its two diagonals.

We know that in a square diagonals bisect each other and if length of side is a, then length of its diagonal = √2 a.

Therefore, GJ=HK = √2×2

Since, diagonal intersect at L , L is mid point of GJ and HK

Therefore, GL = √2×2/2 = √2

Hence, GL = square root of 2

4 0

3 years ago

Which expression represents the ratio of the difference of the two means to Sidney's mean absolute deviation

prohojiy [21]

Answer:

The ratio of the difference of the two means to Sidney's mean absolute deviation = $\frac{4}{3.28}$ = 1.2195

Step-by-step explanation:

P.S - The exact question is -

Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.

Sidney’s Grades Phil’s Grades

Mean 82 78

Mean Absolute Deviation 3.28 3.96

To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?

Proof -

Given that Mean of Sidney Grades = 82

Mean of Phil's Grades = 78

So,

The difference of two means = 82 - 78 = 4

Also,

Given, Mean Absolute Deviation of Sydney = 3.28

Now,

The ratio of the difference of the two means to Sidney's mean absolute deviation = $\frac{4}{3.28}$ = 1.2195

4 0

3 years ago

Write the equation of a line that passes a given point and has the given slope. Answer in standard form. 1. Point (-3,5), m = -7

Likurg_2 [28]

Answer:

y -5 = -7(x +3)
y = 7

Step-by-step explanation:

The point-slope form of the equation can be used for this. It is generally written as ...

y -k = m(x -h) . . . . . line with slope m through point (h, k)

__

1. For m=-7, (h, k) = (-3, 5), the equation is ...

y -5 = -7(x +3)

__

2. For m=0, (h, k) = (4, 7), the equation is ...

y -7 = 0(x -4)

y = 7

_____

Comment on the form of the answer

Since a point and slope are given, "the equation" is appropriately written in point-slope form. For the second problem the simplified version would be ...

y -7 = 0

Sometimes, "the equation" means the answer is expected in slope-intercept form. In that case, a little rearranging is necessary for the first answer. It becomes ...

y = -7x -16

There are perhaps a dozen different forms that a linear equation can be written in. Considering those, "the equation" is somewhat ambiguous. Your curriculum materials may offer a clue as to the form intended.

5 0

3 years ago

The straight line, Line L has an equation of 4x+y=7. Find the equation of the straight line perpendicular to Line L that passes

Jobisdone [24]

Answer:

Step-by-step explanation:

y = -4x + 7

perp. 1/4

y - 3 = 1/4(x + 8)

y - 3 = 1/4x + 2

y = 1/4x + 5

3 0

3 years ago