All categories

3 years ago

Area of circle with diameter of 1 m?

Mathematics

2 answers:

Elena-2011 [213]3 years ago

7 0

Answer:

A = 0.785m²

B = 31400cm²

C = 7850cm²

D = 785,000mm²

Step-by-step explanation:

To solve this question, we'll have to find the area of a circle which is

Area of a circle = πr²

1. The diameter of the circle = 1m

Area of a circle = πr²

r = radius of the circle

π = 3.14

Radius = diameter / 2

Radius = 1 / 2 = 0.5m

Area = 3.14 × (0.5)²

Area = 3.14 × 0.25

Area = 0.785m²

2. Radius = 100cm

Area of a circle = πr²

Area = 3.14 × (100)²

Area = 3.14 × 10000

Area = 31400cm²

3. Diameter = 100cm

Area = πr²

Radius = diameter / 2

Radius = 100 / 2

Radius = 50cm

Area = πr²

Area = 3.14 × (50)²

Area = 3.14 × 2500

Area = 7850cm²

4. Radius = 500mm

Area = πr²

Area = 3.14 × (500)²

Area = 3.14 × 250,000

Area = 785,000mm²

rosijanka [135]3 years ago

5 0

Answer:

A = 0.785m²

B = 31400cm²

C = 7850cm²

D = 785,000mm²

Use the fomula $\pi$ $r^{2}$ to find the area.

If you are having trouble finding the radius divide the diamater by two.

For refrence use 3.14 as pi when multiplying:)

You might be interested in

Oscar, max, norma, pasha, and hank want to ride horses. there are 4 horses- spanky, rita, buttercup, and ebony. in how many diff

Afina-wow [57]

In 9 different ways.
There will be 3 people left and 3 horses, and just multiply 3•3.

6 0

3 years ago

What equation do you get when you solve ............. ky-bf=fy/m for y?

Xelga [282]

Idk use scientific val

5 0

3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$