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9966 [12]
3 years ago
7

Translate the quotient of y and two is equal to eight subtracted from twice y

Mathematics
1 answer:
slamgirl [31]3 years ago
4 0
The quotient means division. So we have one part of the equation. 
y/2 (sorry, the variable thing doesn't work)
Then we know there is an equal mark and the other equation would be 2y-8 because y is multiplied two times and it is subtracted by eight. And then it says it is equal to, so we hate the final equation: y/2=2y-8.
Thank you for the points! Hope I helped!
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IN NEED OF ANSWER :( A flower bed is in the shape of a triangle with one side twice the length of the shortest​ side, and the th
vichka [17]

Answer:

a = 33ft

b= 66ft

c = 48 ft

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • a (shortest side)= a
  • b (second side)=2a (twice the length of the shortest side)
  • c (third side)= a+15 ( 15 feet more than the length of the shortest side)

Since:  

Perimeter = a+b+c

Replacing with the values given:

147 = a+2a+(a+15)

147 = a+2a+a+15

147-15 = a+2a+a

132 = 4a

132/4 = a

33 ft= a  

Substituting a =33 in the other expressions:

b=2a = 2(33) = 66 ft

c= a+15 = 33+15 = 48 ft

3 0
3 years ago
Start at 1000 create a pattern that subtracts 8 from each number. Stop when you have 5 numbers
kifflom [539]
Well, you do 1000-8 then put your answer down.
Answer is 992
Then do 992-8
Answer is 984
Then do 984 - 8
Answer is 976
Then do 976-8
Answer is 968
Then do 968 -8
Answer is 960

Your final answers are 992,984,976,968,960.
7 0
3 years ago
Solve the following quadratic equation for all values of x in simplest form. (x-4)^2=33​
Brrunno [24]

\huge\text{$x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$}

To solve for x, we need to isolate it on one side of the equation.

Take the square root of both sides, making sure to use both positive and negative roots.

\begin{aligned}(x-4)^2&=33\\x-4&=\pm\sqrt{33}\end{aligned}

\sqrt{33} cannot be simplified, so we'll leave it as-is.

Add 4 to both sides to fully isolate x.

x=\pm\sqrt{33}+4

Expand the solution by making two solutions, one where \sqrt{33} is positive and one where it's negative.

x=\sqrt{33}+4,\ x=-\sqrt{33}+4\\x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}

5 0
3 years ago
Read 2 more answers
8. Write an equation of your own that has one real solution. Transform the equation to demonstrate that it has one solution.
miskamm [114]

Answer:

2x  {?}^{2}  + 3x - 1 = 0

6 0
3 years ago
Which expression is equivalent to
maksim [4K]
The answer is C . -7r^2 + 12r -8
5 0
3 years ago
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