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gladu [14]
3 years ago
5

A guy wire supports an antenna tower, as shown at the right. The bottom of the wire is secured in the ground 30 feet from the ba

se of the tower. The top of the wire is secured to the tower at a height of 30 feet above the ground. How long is the wire? Round your answer to the nearest tenth of a foot.
Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

The wire is approximately 42feet long

Step-by-step explanation:

We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.

The hypotenuse side is the length of the wire we are looking for.

Parameters are given as:

Opposite : 30ft

Adjacent: 30ft

Hypotenuse: x feet

The hypotenuse = \sqrt{opp^2 + adj^2}

Hypotenuse =\sqrt{30^2+ 30^2} \approx 42ft

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3 years ago
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A conical-shaped umbrella has a radius of 0.4 m and a height of 0.45 m. Calculate the amount of fabric needed to manufacture thi
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0.76m²

Step-by-step explanation:

In the above question, we are given the following information.

Radius = 0.4m

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To solve this question, The umbrella is CONICAL in shape and it has no BASE, we would be finding the lateral surface area of a cone. Since we are given height and radius :

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8 0
3 years ago
A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire
Anestetic [448]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

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1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

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Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

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6 0
3 years ago
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Answer:

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3 years ago
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