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gladu [14]
3 years ago
5

A guy wire supports an antenna tower, as shown at the right. The bottom of the wire is secured in the ground 30 feet from the ba

se of the tower. The top of the wire is secured to the tower at a height of 30 feet above the ground. How long is the wire? Round your answer to the nearest tenth of a foot.
Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

The wire is approximately 42feet long

Step-by-step explanation:

We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.

The hypotenuse side is the length of the wire we are looking for.

Parameters are given as:

Opposite : 30ft

Adjacent: 30ft

Hypotenuse: x feet

The hypotenuse = \sqrt{opp^2 + adj^2}

Hypotenuse =\sqrt{30^2+ 30^2} \approx 42ft

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Klio2033 [76]

Answer:

In 4 months Wyatt offer an equal number of sandwiches and tacos.

Step-by-step explanation:

We are given the following in the question:

Types of sandwiches = 8

Rate of increase of sandwich = 1 per month

Thus, number of sandwiches in x months will be given by

n_1(x) = 8 + x

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Rate of increase of tacos sandwich = 2 per month

Thus, number of tacos in x months will be given by

n_2(x) = 4 + 2x

Equating the two equations, we get,

n_1(x) = n_2(x)\\8 + x = 4 + 2x\\\Rightarrow x = 4

Thus, in 4 months Wyatt offer an equal number of sandwiches and tacos.

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3 years ago
One canned orange juice is 25% orange juice another is 5% orange juice. How many liters of each should be mixed together in orde
Cerrena [4.2K]

Answer:

X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y  (3)

Replcaing equation (3) into equation (2) we got:

0.75(6.4 -0.2 Y) +0.95 Y = 18.4

And solving for Y we got:

4.8 -0.15 Y +0.95 Y = 18.4

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And solving for X from equation (3) we got:

X= 6.4 -0.2*17 = 3

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

Step-by-step explanation:

For this problem we can work with the concentration of water and orange juice.

Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content

Using the concentration of orange juice we have:

0.25 X + 0.05 Y = 20*0.08  (1)

And for the water we have:

0.75 X + 0.95Y = 20*0.92  (2)

If we solve for X from equation (1) we got:

X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y  (3)

Replcaing equation (3) into equation (2) we got:

0.75(6.4 -0.2 Y) +0.95 Y = 18.4

And solving for Y we got:

4.8 -0.15 Y +0.95 Y = 18.4

0.8 Y = 13.6

Y = 17

And solving for X from equation (3) we got:

X= 6.4 -0.2*17 = 3

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

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A vase in the shape of an oblique cylinder has the dimensions shown. What is the volume of the vase?
fenix001 [56]

The image is missing so i have attached it.

Answer:

Volume = 1.5 litres

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Answer:

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