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Elena-2011 [213]
2 years ago
15

At the market, Meyer buys a bunch of bananas for $0.65 per pound and a frozen pizza for $4.99. The total for his purchase was $6

.94, without tax. How many pounds of bananas did Meyer buy?
Mathematics
2 answers:
saw5 [17]2 years ago
8 0
3 pounds
6.94-4.99=1.95
1.95*0.65=3
3
Harlamova29_29 [7]2 years ago
7 0

Answer:

Well, 6.94 - 4.99 = 1.95 also that divided by 0.65 = 3 So it is 3  pounds of bananas

Step-by-step explanation:

P.S can I have brainliest?

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3 years ago
At an effective annual interest rate of i > 0, each of the following two sets of payments has present value K: (i) A payment
IgorLugansk [536]

Answer:

The present value of K is, K=251.35

Step-by-step explanation:

Hi

First of all, we need to construct an equation system, so

(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}

(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

Then we equalize both of them so we can find i

(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

To solve it we can multiply (3)*(1+i)^{4} to obtain (1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}), then we have 225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}.

This leads to a third-grade polynomial 169i^{3}+451i^{2}+395i-112=0, after computing this expression, we find only one real root i=0.2224.

Finally, we replace it in (1) or (2), let's do it in (1) K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35

8 0
3 years ago
Find the geometric mean between each pair of numbers. sq root 49 and sq root841
vodomira [7]

<u>Answer:</u>

The geometric mean between each pair of numbers \bold{\sqrt{49} \text { and } \sqrt{841} \text { is } 14.24}

<u>Solution:</u>

The Geometric mean between two numbers a and b is given as  Geometric mean = \bold{\sqrt{ab}}   --- eqn 1

The Geometric Mean is a special type of average where we multiply the numbers together and then take a square root for the numbers.

From question, given that two numbers are \sqrt{49} and \sqrt{841}

Hence we can say “a” = \sqrt{49} =7  

Similarly “b” = \sqrt{841} = 29  

We have to find the geometric mean between “7” and “29”

By using equation 1,  

Geometric mean between 7 and 29 = \sqrt{7 \times 29} = \sqrt{203} = 14.24

Hence the geometric mean between \sqrt{49} \text { and } \sqrt{841} \text { is } 14.24

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Answer:

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Step-by-step explanation:

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