All categories

3 years ago

PLEASE HELP!!!! I know the answer, but I don’t know how to solve the problem!!!

Mathematics

1 answer:

nevsk [136]3 years ago

4 0

To start you need to get rid of the denominator so you add -4 by 8 to get 4 then multiply both sides by 4 to remove the denominator giving you -8= 5-y1. After that subtract 5 from both sides giving you -13= -y1, dividing by -1 you then get y1= 13

You might be interested in

A game room has a floor that is 100 feet by 30 feet. A scale drawing of the floor on grid paper uses a scale of 3 units:5 feet.

Ghella [55]

3 units/ 5 feet = 60 units/ 100 feet
3 units/ 5 feet = 18 units/ 30 feet

The dimensions of the scale drawing are 60 units by 18 units.

Hope this helps!

7 0

3 years ago

Patrick paid $4.00 for 5 organic peaches. How much did he pay per peach

leonid [27]

Answer:

80 cents

Step-by-step explanation:

divide the price by 5

4/5=.8

6 0

3 years ago

Read 2 more answers

What is the value of y in the equation 4 + y = −3? 7 1 −1 −7

Natasha_Volkova [10]

Answer:

-7 is your answer

Step-by-step explanation:

Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other.

4 + y = -3

Subtract 4 from both sides

4 (-4) + y = -3 (-4)

y = -3 - 4

y = -7

-7, or (D) is your answer

6 0

4 years ago

Read 2 more answers

Jenny can swim 10 laps In 5 minutes. How many laps should she swim in 1/3 of an hour?

DIA [1.3K]

1/3 of an hour is 20 minutes. If show 10 laps in 5 minutes, just divide 20 by 5, which gives you 4, then multiply 4 times 10. She can swim 40 laps in 1/3 of an hour. Hope that helps. Mark Brainliest if it does. Thank you!

4 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

3 years ago