Answer:
Given
Step-by-step explanation:
Consider triangle ABD and triangle DCA,
AC=BD ( given that they are diameters)
Diameters of the same circle are equal
AD=AD (common side for both triangles)
<BAD= <CDA (angles in semicircles are 90°)
So since the right angle, hypotenuse and side are equal..
ABD is congruent to CDA
(Rhs congruence rule)
Hence proved..
This is the answer if you mean 719-26
700-30= 670
Answer:
Quotient: x+7
Remainder: -2
Step-by-step explanation:
Divide the terms (x² ÷ x =x)↓
(x² + 11x + 26) ÷ (x + 4) =x
Subtract x² + 4x (You have to the sign if each term)
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
Divide the terms (7x ÷ x = 7)
x² + 11x + 26) ÷ (x + 4) =x + 7
Multiply the quotient by the dividend (x + 4) × 7 = 7x+28
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
7x + 28
------------------
= -2 Remainder
35 / 5 = 7 ; also 49 /7 = 7
So
? = 8 x 7 = 56
Answer
Missing side length = 56