<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
<span>Item Number of Liters Percentage of LemoneA 4 14%B x 8%Result 4+x 10%
For a mixture of solutions to form a resulting solution, we know
V1 * N1 + v2 * N2 = V * N
where, V1 = Volume of mixture of 1 N1 = Concentration of mixture 1V2 = Volume of mixture of 2 N2 = Concentration of mixture 2
V = volume of mixture N = Concentration of mixture
So solving we get:
(4+x)*10 = 4*14 + x * 8or, 10x-8x = 4*14-4*10or, 2x = 16or x = 8
so 8 litres of the solution B must be added to the solution<span>
</span></span>
First find midpoint of AB and lastly find the length of midpoint and C
