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3 years ago

Find the distance between the points (4, 6) and (2, -6). Round to the nearest tenth.

Mathematics

1 answer:

Deffense [45]3 years ago

5 0

Answer:

The correct answer is B.12.2

Step-by-step explanation:

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Divers in a competition are scored by an international panel of judges. The highest and the lowest scores are dropped. The total

Fudgin [204]

From the statements given in the problem, we can say that:

Final Score = (total of the remaining scores) * degree of difficulty * 0.6

Therefore:

97.2 = (total of the remaining scores) * 4.0 * 0.6

total of the remaining scores = 40.5

Therefore the judges could have scored which has a total of 40.5

6 0

2 years ago

Read 2 more answers

Find the x-intercept and the y-intercept of 2x + 6y =24

viktelen [127]

Answer:

x-intercept = 12, y-intercept = 4

Step-by-step explanation:

To find the x and y intercept, substitute 0 in for both values.

Substitute 0 into x:

2(0) + 6y = 24

6y = 24

Divide each side by 6:

y = 4

Substitute 0 into y:

2x + 6(0) = 24

2x = 24

Divide each side by 2:

x = 12

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2 years ago

811+901+88+5 the sum is

bogdanovich [222]

that all equal 1805 .......

8 0

2 years ago

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In a class of 100 students, 25 have hardcover and 75 students have paperback textbooks. If you randomly choose 15 students in th

Gnom [1K]

Answer:

23.72% probability that 3 of them have hardcover texts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

If you randomly choose 15 students in this class, find the probability that 3 of them have hardcover texts.

Desired outcomes:

3 with hardcover texts, from a set of 25.

15-3 = 12 with paperback texts, from a set of 75. So

$D = C_{25,3}*C_{75,12} = \frac{25!}{3!(22)!}*\frac{75!}{12!(63)!} = 6 \times 10^{16}$

Total outcomes:

15 students from a set of 100. So

$T = C_{100,15} = \frac{100!}{15!85!} = 2.53 \times 10^{17}$

Probability:

$P = \frac{D}{T} = \frac{6 \times 10^{16}}{2.53 \times 10^{17}} = 0.2372$

23.72% probability that 3 of them have hardcover texts.

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2 years ago

A man sold a square field of side 35 m and a

Novosadov [1.4K]

Answer:

Total area of field sold(35*35)+(51*25)=2500

Area of square field is 2500

One side = $\sqrt{a}$ = 50

So, the perimeter of the square(4*a)=4*50=200

Cost of fencing = 200*1.5 usd = $300

Step-by-step explanation:

6 0

2 years ago