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aleksley [76]
3 years ago
14

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

Mathematics
2 answers:
Deffense [45]3 years ago
7 0
So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.

You know that you have

90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle

sin19 = x/15
15sin19 = x
x = 2.2

Now do Pythagoras c^2-b^2=a^2

a = 14.8

So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)

ahrayia [7]3 years ago
5 0

Answer:

D.  4.9 units, 14.2 units

Step-by-step explanation:

By working in reverse, doing arctan( small side / big side) we can deduce it to answer D, seeing as

4.9/14.2 ~= 0.34507

tan^{-1}(0.34507) = 19.04degrees

Which rounds out to 19degrees in the tenths.

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Overline MD cong overline LS additional information is necessary to show that triangle MTD cong triangle LGS by SSS?
aivan3 [116]

Answer:

TD \cong GS

Step-by-step explanation:

See comment for complete question

Given:

TM \cong GL

MD \cong LS

Required

The information that shows \triangle MTD \cong \triangle LGS by SSS

By SSS implies that, the three sides of both triangles are congruent

Already, we have:

TM \cong GL

MD \cong LS

The third side of \triangle MTD is TD

The third side of \triangle LGS is GS

So, for both to be congruent by SSS, the third sides must be congruent

i.e.

TD \cong GS

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olga_2 [115]

Answer:

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Answer:

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Step-by-step explanation:

Hey!

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