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monitta
3 years ago
13

Help please!!!! Asap!! math whizzes!!!

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0

Answer:

5xy^3 \sqrt{3x}

Step-by-step explanation:

The radical \sqrt{75x^3y^6} can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.

\sqrt{75x^3y^6} =\sqrt{3*25*x^2*x*y^6} =5xy^3 \sqrt{3x}

25 is a perfect square and is 5 outside the radical.

x^2 is a perfect square and is x outside the radical.

y^6 is a perfect square and is y^3 outside the radical.

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In a science experiment, Shelly has to weigh a compound in grams. The balance in her school measures in milligrams (mg). Shelly
exis [7]

Answer:

8.45 grams

Step-by-step explanation:

In a science experiment, Shelly has to weigh a compound in grams. The balance in her school measures in milligrams (mg). Shelly finds that the weight of the compound is 8,450 mg. What is the value in grams (g) that Shelly should enter?

1 mg = 0.001 g

8450 mg = x

Cross Multiply

= 8450 × 0.001 g

= 8.45 g

Therefore, Shelly should enter 8.45 grams

7 0
3 years ago
Find the next three terms in this sequence: 5120, 1280, 320, 80, ...
dimaraw [331]
This seems to be dividing by 4, so the next numbers are 20, and then 5. If there is a 3rd, it's 1.25
8 0
3 years ago
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

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5 0
3 years ago
Si Martha retira de su cuenta el 10% para los transportes del mes. ¿Cuál es el nuevo saldo de la cuenta?
notsponge [240]

Respuesta:

0,9 veces

Explicación paso a paso:

Deje que la cantidad en la cuenta de Martha se denote como x, que es la cantidad en la cuenta = x

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El porcentaje total siempre será del 100%

Por lo tanto, si se retira el 10%, entonces; el porcentaje restante es:

Porcentaje total: porcentaje gastado en transporte

(100% - 10%) * monto en cuenta

90% * x = 0,9 * x = 0,9x

Saldo de cuenta nueva = 0.9x

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AVprozaik [17]
By setting up proportions and cross multiplying, the height would be 990.8. 
5 0
3 years ago
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