Question

Help please!!!! Asap!! math whizzes!!!

Answer 1

Answer:

$5xy^3 \sqrt{3x}$

Step-by-step explanation:

The radical $\sqrt{75x^3y^6}$ can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.

$\sqrt{75x^3y^6} =\sqrt{3*25*x^2*x*y^6} =5xy^3 \sqrt{3x}$

25 is a perfect square and is 5 outside the radical.

$x^2$ is a perfect square and is x outside the radical.

$y^6$ is a perfect square and is $y^3$ outside the radical.