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monitta
2 years ago
13

Help please!!!! Asap!! math whizzes!!!

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
7 0

Answer:

5xy^3 \sqrt{3x}

Step-by-step explanation:

The radical \sqrt{75x^3y^6} can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.

\sqrt{75x^3y^6} =\sqrt{3*25*x^2*x*y^6} =5xy^3 \sqrt{3x}

25 is a perfect square and is 5 outside the radical.

x^2 is a perfect square and is x outside the radical.

y^6 is a perfect square and is y^3 outside the radical.

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The width of a rectangle is 12 inches more than the length. The perimeter is 76 inches. Find the width and the length.
stira [4]

Answer:

The length of the rectangle is 13 inches and its width (13 + 12) is 25 inches.

Step-by-step explanation:

You have to consider the formula of the perimeter = 2·length + 2·width.

If we call "x" to the length ⇒ width = x + 12 .

Perimeter = 2x + 2·(x + 12) ⇒ Perimeter = 2x + 2x + 24

⇒Perimeter = 4x + 24. ⇒ 76 = 4x + 24 ⇒ 76 - 24 = 4x ⇒52 = 4x

⇒ 52/4 = x ⇒ x = 13.

So, the length of the rectangle is 13 inches and its width (13 + 12) is 25 inches.

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2 years ago
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Simplify the square root of 96
Tamiku [17]
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3 years ago
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