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4 years ago

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The method used to factor trinomials of the form ax^2+bx+c can also be used to factor binomials of the form px^2+q by realizing

that, in this case, _____. A. a = 0 B. b = 0 C. c = 0 D. x = 0

1 answer:

Vanyuwa [196]4 years ago

3 0

C.) c=0, in some cases. It actually happens pretty often, and it will mean the y-intercept is (0,0) and there is an x-intercept also at (0,0)

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olga nikolaevna [1]

Answer:

Its would be E

Step-by-step explanation:

1.5x + 3 = -2x + 3 -1.5x = -2x 0.5x = 0 x = 0

Which is 0,3 and it’s only one solution.

5 0

3 years ago

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Calculate the sample standard deviation for the following data set. If necessary, round to one more decimal place than the large

mamaluj [8]

Answer:

$s = 0.0394$

Step-by-step explanation:

Given:

0.612 0.523 0.606 0.631 0.584 0.592 0.644 0.597 0.639 0.607 0.564 0.673

Required

Calculate the sample standard deviation

First, calculate the mean

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.612 +0.523 +0.606 +0.631+ 0.584 + 0.592+ 0.644 +0.597 +0.639 +0.607 +0.564+ 0.673}{12}$

$\bar x = \frac{7.272}{12}$

$\bar x = 0.606$

The sample standard deviation is then calculated using:

$s = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sum (x - \bar x)^2 = (0.612 -0.606)^2+(0.523 -0.606)^2+(0.606 -0.606)^2+(0.631 -0.606)^2+(0.584 -0.606)^2+(0.592 -0.606)^2+(0.644 -0.606)^2+(0.597 -0.606)^2+(0.639 -0.606)^2+(0.607 -0.606)^2+(0.564 -0.606)^2+(0.673 -0.606)^2$

$\sum (x - \bar x)^2 = 0.017098$

So, we have:

$s = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$s = \sqrt{\frac{0.017098}{12-1}}$

$s = \sqrt{\frac{0.017098}{11}}$

$s = \sqrt{0.00155436363}$

$s = 0.0394$ -- approximated

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3 years ago

Answer so I can past one of my test

stiks02 [169]

Answer: D

take 5/15 and simplify to 3/1

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3 years ago

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Simplify: (21+3 g6/3-18)3

BartSMP [9]

Answer: Hope this helps

Step-by-step explanation:

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3 years ago

Integers can be negative numbers. 9TRUE OR FALSE

Maurinko [17]

Answer:

This is true! :)

Step-by-step explanation:

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3 years ago