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2 years ago

Drag each equation to the model and situation it matches. (Picture) *I will give a brainliest

Mathematics

1 answer:

arlik [135]2 years ago

7 0

Answer:

First model gets the equation: y = 2 . 2^z

Second model gets the equation: y = 4^z

Third model gets the equation: y: = 4 . 2^z

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If fx = 5x - what is the value of f(5)?

ra1l [238]

Answer:

Step-by-step explanation:

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2 years ago

Please help!!!!!

vampirchik [111]

Answer:

Step-by-step explanation:

Consider the quadratic equation, we have

$ax^2+bx+c=0$

Dividing the equation by a, we get

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

Put $\frac{c}{a}$ on the other side,

$x^2+\frac{b}{a}x=\frac{-c}{a}$

Add $(\frac{b}{2a})^2$ on both the sides,

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2$

completing the square, we have

$(x+\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2$

Now, solving for x,

$x+\frac{b}{2a}={\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}$

$x=\frac{-b}{2a}{\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}$

Multiply right side by $\frac{2a}{2a}$ ,

$x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}$

which is the required quadratic formula.

8 0

3 years ago

Read 2 more answers

Calculate the distance between the points L = (1, -1) and J=(4,-9) in the coordinate plane.

Blizzard [7]

Answer:

8.54

Step-by-step explanation:

distance formula is d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

plug in the coordinates the answer is 8.54

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3 years ago

Which is a name for the angle shown? Select all that apply

sladkih [1.3K]

Answer:

Step-by-step explanation:

<h2>Well, the angle is an acute angle and <CDE is what would connect to make an acute angle. Easy.</h2>

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3 years ago

Can someone help me out

Nana76 [90]

Answer:

it is D

(1.5-6)/-2-4 =0.75

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2 years ago