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Rama09 [41]
3 years ago
8

Ben is going bowing this weekend. It will cost $5 for the shoe rental plus $6 per game bowled. Which equation models the cost, c

, for Ben to bowl g games?
Mathematics
2 answers:
Nostrana [21]3 years ago
8 0

Answer:

The required equation is modeled as :

c = 5 + 6·g

Step-by-step explanation:

Cost price of the shoe rental = $5

Cost of the per game bowled = $6

Let the total cost for the games played = $c

Let the number of games bowled be g

⇒ Cost of the games played = $ 6·g

Now, we need to model the equation for the cost, c, for Ben to bowl g games.

Thus, The required equation is modeled as :

c = 5 + 6·g

elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

C(g) = 5 + 6g

Step-by-step explanation:

Let

C be the cost function for Ben

and  

g be the number of games

As the shoe rental is paid for all the games, it will be added only once. The variable on which the cost will be dependent is g. The number of games will directly affect the cost function. Here g is independent variable.

So, mathematically writing,

C(g) = 5 + 6g

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Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
Calculate cose to two decimal places.
Monica [59]

Answer:

B. 0.69

Step-by-step explanation:

Law of Cosines: cos A = (b² + c² - a²) / 2bc

cosθ = (7² + 11² - 8²) / 2*7*11 = 106/154 = 0.688 ≈ 0.69

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the formula F=9/5C+32 changes a temperature reading from the Celsius scale C to the Fehrenheit scale F. What temperature measure
cestrela7 [59]

Answer:

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Step-by-step explanation:

F=(9/5)c + 32

F=(9/5)(-5) + 32

F=(-9) + 32

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3 years ago
A continuous random variable may assume :
vova2212 [387]

Answer:

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Step-by-step explanation:

Continuous Random Variable:

  • A continuous random variable can take any value within an interval.
  • Thus, it can take infinite values since there are infinite numbers in an interval.
  • A continuous variable is a variable whose value is obtained by measuring.
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Option A) any numerical value in an interval or collection of intervals

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