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ser-zykov [4K]
2 years ago
6

Halp mi now. pls pls plsp lls plsp pls

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
7 0

Answer:

-r+5<-3

Step-by-step explanation:

plug in 19 to the equation inequality

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sorry can't help search it up on the internet

Step-by-step explanation:

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3 years ago
Alice works at a health care facility. She has measured the hemoglobin levels of 200 people. The data follows a normal distribut
rewona [7]
Since the data follows a normal distribution, the 68-95-97 rule can be used to describe the number of people falling under N standard deviations from the mean. Since the standard deviation is 1, hemoglobin levels of 13 -15 g/dL contains 68% of the sample, or 136 people. This means the 32 people have less than 13 g/dL and 32 people have more than 15 g/dL.
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Can someone help me this is really confusing????? What is the solution set for the open sentence with the given replacement set?
IgorLugansk [536]

The answer is:

3

w^2 - 1 = w + 5

3^2 - 1 = w + 5

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6 0
3 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ

= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ

= 8[6561/4]∫(cosθsinθ)dθ

= 13122∫(cosθsinθ)dθ

Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

= -13122/4[cos4π - cos(0)]

= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
3 years ago
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