F(x)=-2e^x
x=3
f(3)=-2e^3
pemdas so exponents first
e^3
e=2.718281828454590
cube that
20.0855
now we have
-2 times 20.0855=-40.1711
answer should be -40.1711
(I see what you did wrong, if -6=-2 times e^3, divide -2, 3=e^3, maybe you just put -2 times 3 by mistake)
Start with assigning each person with a variable to represent their height
Ebi: e
Jose: j
Derell: d
Asami: a
Ebi'd height was 2.5 cm greater than Jose's height
j + 2.5 = e
Jose's height was 3.1 cm greater than Derell's
d + 3.1 = j
Derell's height is 0.4 cm less than Asami's height
a - 0.4 = d
Ebi is 162.5 cm tall
e = 162.5
So, plug in 162.5 into any of the above equations were there is a variable of e
j + 2.5 = e
j + 2.5 = 162.5
Subtract 2.5 from both sides of the equation
j = 160 cm
Jose's height is 160 cm
Now, plug in 160 into any of the above equations where there is a j
d + 3.1 = j
d + 3.1 = 160
Subtract 3.1 from both sides of the equation
d = 156.9 cm
Derell's height 156.9 cm
so, plug in 156.9 into any of the above equations where there is a d
a - 0.4 = d
a - 0.4 = 156.9
Add 0.4 on both sides of the equation
a = 157.3 cm
Asami's height is 157.3 cm
I think it’s B but don’t at me
are there any answers you can choose from
Answer:
Hello,
in order to simplify, i have taken the inverses functions
Step-by-step explanation:
![\int\limits^\frac{1}{2} _{-1} {(-2x^2-x+1)} \, dx \\\\=[\frac{-2x^3}{3} -\frac{x^2}{2} +x]^\frac{1}{2} _{-1}\\\\\\=\dfrac{-2-3+12}{24} -\dfrac{-5}{6} \\\\\boxed{=\dfrac{9}{8} =1.25}\\](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%20%7B%28-2x%5E2-x%2B1%29%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B%5Cfrac%7B-2x%5E3%7D%7B3%7D%20-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%2Bx%5D%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B-2-3%2B12%7D%7B24%7D%20-%5Cdfrac%7B-5%7D%7B6%7D%20%5C%5C%5C%5C%5Cboxed%7B%3D%5Cdfrac%7B9%7D%7B8%7D%20%3D1.25%7D%5C%5C)
